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Tema [17]
3 years ago
8

Please help math 25 points

Mathematics
2 answers:
STALIN [3.7K]3 years ago
7 0
C is the answer! hope it helps
asambeis [7]3 years ago
6 0

The answer is the letter C.

Check out desmos, its a great graphing calculator!!

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5x-7=4<br> ------<br> 7<br><br> где полосочки это дробная черта
otez555 [7]

Answer:

5x-6+7

That's the answer

4 0
2 years ago
Look at the image for the question?
Oxana [17]

Answer:

396 in ^3

Step-by-step explanation:

The volume of a rectangular prism is

V = l*w*h  where l is the length, w is the width, and h is the height

V = 12 * 3 * 11

V = 396 in ^3

6 0
3 years ago
Help pls ;) <br> Find the geometric mean of 14 and 20
valkas [14]

Answer:

geometric mean of 14 and 20 = 17. geometric mean of 2 and 32 = 17. geometric mean of 9 and 25 = 17. geometric mean of 25 and 35 = 30.

Step-by-step explanation:

6 0
3 years ago
25 POINTS (for question one) How should I solve this? I know it has something to do with Pythagorean Theorem and area but not su
Pavel [41]
The pythagorean theorem states that a^2+b^2=c^2 where c is the hypotenuse and a and b are the legs.

The easiest way to divide his fields is to give one son the field that represents the side length of the hypotenuse and his other son the other fields. This works because a squared and b squared adds to exactly c squared, making the areas equal.
5 0
3 years ago
Suppose Salma places $5500 in an account that pays 2% interest compounded each year. Assume that no withdrawals are made from th
e-lub [12.9K]

Answer:

Part a) \$5,610  

part b) \$5,722.20  

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

Part a) Find the final investment year one

in this problem we have  

t=1\ year\\ P=\$5,500\\ r=2\%=2/100=0.02\\n=1  

substitute in the formula above

A=5,500(1+\frac{0.02}{1})^{1*1}  

A=5,500(1.02)^{1}  

A=\$5,610  

Part b) Find the final investment year 2

in this problem we have  

t=2\ years\\ P=\$5,500\\ r=2\%=2/100=0.02\\n=1  

substitute in the formula above

A=5,500(1+\frac{0.02}{1})^{1*2}  

A=5,500(1.02)^{2}  

A=\$5,722.20  

7 0
3 years ago
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