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MissTica
3 years ago
12

Marcy has 150 to buy packages of hotdogs and hamburgers for her booth at the carnival. Grocery store she found packages of hotdo

gs cost six packages of hamburgers cost 20
Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

Part (A): The required equation will be: 6d+20b=150

Part (B):The required equation will be: d=\frac{150-20b}{6}

Part (C):The required equation will be: b=\frac{150-6d}{20}

Step-by-step explanation:

Consider the provided information.

Let d represents number of packages of hot dogs and b represents the number of packages of hamburgers.

Part (a)

It is given that the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20.

The required equation will be: 6d+20b=150

Part (b) Solve the above equation for d.

Subtract 20b from both sides.

6d=150-20b

Divide 6 from both sides.

d=\frac{150-20b}{6}

The required equation will be: d=\frac{150-20b}{6}

Part (c) Solve the equation for b.

Subtract 6d from both sides.

20b=150-6d

Divide 20 from both sides, we get

b=\frac{150-6d}{20}

The required equation will be: b=\frac{150-6d}{20}

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5 0
3 years ago
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Does 5 go into 100 equally
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6 0
3 years ago
How to solve for W because I honestly don’t understand anything
erastova [34]

we do 2x-1/y=w+2/2z

2x-1/y we multiple each side y

2x-1/y×y=2x-1

then w+2/2z

we said×2z×2z

then we got

w+2

later

2x-1=w+2=

then 1 become another side

which is 1+2=3

then

w=3-2x

I hope it's correct

4 0
4 years ago
Read 2 more answers
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