Answer:
i hehe
Step-by-step explanation:
Given Information:
number of trials = n = 1042
Probability of success = p = 0.80
Required Information:
Maximum usual value = μ + 2σ = ?
Minimum usual value = μ - 2σ = ?
Answer:
Maximum usual value = 859.51
Minimum usual value = 807.78
Step-by-step explanation:
In a binomial distribution, the mean μ is given by
μ = np
μ = 1042*0.80
μ = 833.6
The standard deviation is given by
σ = √np(1 - p)
σ = √1042*0.80(1 - 0.80)
σ = √833.6(0.20)
σ = 12.91
The Maximum and Minimum usual values are
μ + 2σ = 833.6 + 2*12.91
μ + 2σ = 833.6 + 25.82
μ + 2σ = 859.51
μ - 2σ = 833.6 - 25.82
μ - 2σ = 807.78
Therefore, the minimum usual value is 807.78 and maximum usual value is 859.51
Answer:
The number of ways is 13,800 ways
Step-by-step explanation:
In this question, we are tasked with calculating the number of ways to form 3-digits codes from 25 different numbers given that no repetition is allowed.
Now, for the first digit, we have all the 25 numbers completely wanting to take a spot. Now, in how many ways can we choose a single out of 25, that would be 25 ways
Now, we have 24 numbers left, and we are trying to pick one, the number of ways this can be done is 24 ways also
for the last digit, we have 23 numbers and we are selecting just one, the number of ways this can be done is 23 ways too
Thus, the cumulative number of ways would be 25 * 24 * 23 = 13,800 ways
