So, we have to solve two different equations, depending of the possible range for the variable. We have to remember about these ranges when we decide to accept or discard the solutions:

Suppose that $p+2\geq 0 \iff p \geq -2$

In this case, the absolute value doesn't do anything: the equation is

$p+2 = 10 \iff p = 10-2 = 8$

We are supposing $p \geq -2$ , so we can accept this solution.

Now, suppose that $p+2 < 0 \iff p < -2$ . Now the sign of the expression is flipped by the absolute value, and the equation becomes

$-p-2 = 10 \iff -p = 12 \iff p = -12$

Again, the solution is coherent with the assumption, so we can accept this value as well.

3 0

3 years ago

I need helpppppppppppp

kakasveta [241]

Answer:

1/4 I'm pretty sure

Step-by-step explanation:

because half of the class already went to the afternoon session and 3/4 went to see the movie

4 0

3 years ago

Read 2 more answers