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2 years ago

HELP URGENT!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Ainat [17]2 years ago

5 0

First find the area of the whole square. Even the part that isn't part of the area. Then find the area of the spots that aren't part of the shape. Then subtract that area from the area of the whole thing.

15×18=270
(9x12)+(4×5)=128
270-128=142

Area= 142ft^2

maria [59]2 years ago

3 0

Think of the shape as being three rectangles stacked on top of each other. Lets call the top shape r1, the middle shape r2, and the bottom shape r3.

We know that all of them together have a height of 15 ft, the height of r1 is 4 ft and the height of r2 is 5 ft. So the height of r3 must be 15-4-5=6ft.

We know that all of them together have a width of 18 ft, width of r1 is 1 ft, and the width of r3 is 18 ft. The width of r2 must equal 5 ft plus the width of r1, 5+1=6.

Finally we use the equation for the area of a rectangle, Area=base(width)*height. Find the area of each individual rectangle and add the three areas together to get the area of the whole shape.

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What is the answer of this? thanks. 15 pts

Vikentia [17]

3.(6^(12-10)) = 3× 6^2 =3× 36 =108

5 0

3 years ago

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What is the frequency of the sinusoidal graph ?

disa [49]

Answer:

The frequency of the given sinusoidal graph is 4.

Step-by-step explanation:

The frequency of a sinusoidal graph is the number of cycles it completes in the interval 0 to 2π radians.

From the given sinusoidal graph it is noticed that the the graph complete its one cycle in the interval 0 to $\frac{\pi}{2}$ .

If the complete its one cycle in $\frac{\pi}{2}$ , then the number of cycles completed by the graph in the inteval 0 to 2π is

$\frac{\pi}{2}\times frequency=2\pi$

$frequency=2\pi \times \frac{2}{\pi}$

$frequency=4$

Therefore the frequency of the given sinusoidal graph is 4.

7 0

3 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

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3 years ago

Edwin walks for 2 hours. He walks 1 miles in the first hour, 1 miles in the second hour and 1 of the total distance in the last

Free_Kalibri [48]

Is it 3 miles? From what you wrote, I believe this would be the answer.

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3 years ago

Fiona needs $62 to go on a field trip. She has saved $10.50. She earns $6.50 per hour cleaning her neighbor's garden, and she ea

Katyanochek1 [597]

(6.50 x 6)+(5.25 x 2)+10.50=60
No, unfortunately, she can't go on the field trip. She is off by two dollars.

8 0

3 years ago

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