HELP URGENT!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Ainat [17]3 years ago

5 0

First find the area of the whole square. Even the part that isn't part of the area. Then find the area of the spots that aren't part of the shape. Then subtract that area from the area of the whole thing.

15×18=270
(9x12)+(4×5)=128
270-128=142

Area= 142ft^2

maria [59]3 years ago

3 0

Think of the shape as being three rectangles stacked on top of each other. Lets call the top shape r1, the middle shape r2, and the bottom shape r3.

We know that all of them together have a height of 15 ft, the height of r1 is 4 ft and the height of r2 is 5 ft. So the height of r3 must be 15-4-5=6ft.

We know that all of them together have a width of 18 ft, width of r1 is 1 ft, and the width of r3 is 18 ft. The width of r2 must equal 5 ft plus the width of r1, 5+1=6.

Finally we use the equation for the area of a rectangle, Area=base(width)*height. Find the area of each individual rectangle and add the three areas together to get the area of the whole shape.

You might be interested in

Why can you use cross products to solve the proportion 18/5 equals x/100 for x?

blondinia [14]

18 x
--- = ----
5 100

18×100 = 5×x

1800 = 5x
------- ----
5 5

360 = x
Hope this helps!!!

5 0

3 years ago

I am doing online class and I am looking for a little help please

kati45 [8]

The domain is about how far left-to-right the graph goes.
In relation to the x-axis, the graph starts at x = –3 (with an open circle at –3) and then continues over to the right forever.
This is the shown in the picture with the red markup.
In interval notation, this is (-3, infinity).

Remember to use that left-to-right orientation for interval notation!

The range is in turn about how low to how high the graph goes.
On the graph, I’d do the same thing I did on the red marked up graph and compare the graph to the y-axis.
The graph starts down at y = –5 (with an open circle at –5) and then continues on up forever.
In interval notation, this is (-5, infinity).