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levacccp [35]
3 years ago
9

HELP URGENT!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Ainat [17]3 years ago
5 0
First find the area of the whole square. Even the part that isn't part of the area. Then find the area of the spots that aren't part of the shape. Then subtract that area from the area of the whole thing.

15×18=270
(9x12)+(4×5)=128
270-128=142

Area= 142ft^2
maria [59]3 years ago
3 0
Think of the shape as being three rectangles stacked on top of each other.  Lets call the top shape r1, the middle shape r2, and the bottom shape r3.

We know that all of them together have a height of 15 ft, the height of r1 is 4 ft and the height of r2 is 5 ft. So the height of r3 must be 15-4-5=6ft.

We know that all of them together have a width of 18 ft, width of r1 is 1 ft, and the width of r3 is 18 ft. The width of r2 must equal 5 ft plus the width of r1, 5+1=6.

Finally we use the equation for the area of a rectangle, Area=base(width)*height. Find the area of each individual rectangle and add the three areas together to get the area of the whole shape.
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In the figure, AB ll CD and<br>m4=85<br>What is m5​
AveGali [126]

Answer:

85°

Step-by-step explanation:

m∠4  measures 85 degrees.

m∠4 and m∠5 are alternate interior angles.

The alternate interior angles theorem states that <u>all pairs of alternate interior angles are congruen</u>t, or equal.

m∠4 ≅ m∠5

So, m∠5 should also be 85° as well as m∠4.

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3 years ago
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maw [93]

Answer:

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Step-by-step explanation:

5 0
3 years ago
A=16,b=63<br> Find the missing angle
Julli [10]
180 - 16 - 63 = 101.  The remaining angle is 101*  

Hope I helped!
6 0
4 years ago
Read 2 more answers
I NEED HELP PLS I WILL GIVE CROWN: Mr. Crow, the head groundskeeper at High Tech Middle School, mows the lawn along the side of
katrin2010 [14]

Answer:

Mr. Crow dimension of the lawn = 85 × 40

Area of the lawn = 3250 square feet

Step-by-step explanation:

Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

Thus, the perimeter of the rectangle = 2( 2x+5+x) = 2(3x+5) = 6x+10

If x = 30,  the perimeter of the rectangle = 6 × 30 + 10 = 190 < 250

Thus, x ≠ 10.

If x = 50,  the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x  = 40, the  the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x  = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.Let x represents the width of the rectangle,

Then According to the question,

The length of the rectangle = 2 x + 5

Also it is given that the perimeter of the rectangle = 250 feet.

But we know that the perimeter of the rectangle = 2 × ( length + width)

Thus, the perimeter of the rectangle = 2( 2x+5+x) = 2(3x+5) = 6x+10

If x = 30,  the perimeter of the rectangle = 6 × 30 + 10 = 190 < 250

Thus, x ≠ 10.

If x = 50,  the perimeter of the rectangle = 6 × 50 + 10 = 310 > 250

Thus, x ≠ 50

If x  = 40, the  the perimeter of the rectangle = 6 × 40 + 10 = 250 = 250

Thus, x = 40

Therefore, the width of the rectangle, x  = 40 feet.

And, the length of the rectangle, 2 x + 5 = 2 × 40 + 5 = 85 feet.

1) The dimension of the rectangle = 85 × 40

2)The area of the rectangle = length × width = 85 × 40  = 3250 square feet.

8 0
3 years ago
A box 4 cm by 6 cm by 8 cm is painted on all six faces and then cut into cubes with the 2 cm sides. How many of these cubes have
VMariaS [17]

Answer:

  4

Step-by-step explanation:

2 cubes on each 6 × 8 face will have one surface painted. The sides of dimension 4 cm do not have enough width to have any cubes with only one face painted.

Hence, there are a total of 4 cubes with one face painted.

8 0
4 years ago
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