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nikdorinn [45]
3 years ago
12

Find the equation of the line passing through the following point.​

Mathematics
1 answer:
Valentin [98]3 years ago
7 0

y+0=1*(x+0) or y=x

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The quotient of a number and 2<br>​
alexgriva [62]

Answer:

what is the question?

Step-by-step explanation:

.????

4 0
3 years ago
What's 24 - 5.9 and how do you show your work
ziro4ka [17]

Answer:

18.1

Step-by-step explanation:

24-5.9=18.1

8 0
3 years ago
5<img src="https://tex.z-dn.net/?f=5%5E%7B56%7D%20x%205%5E%7B22%7D%20x%205%5E%7B-96%7D" id="TexFormula1" title="5^{56} x 5^{22}
Akimi4 [234]

Answer:

\frac{ {11}^{56} }{ {5}^{18} }

Step-by-step explanation:

{55}^{56}  \times  {5}^{22}  \times  {5}^{ - 96}

=  {55}^{56}  \times  {5}^{ - 74}

=  {11}^{56}  \times  {5}^{56}  \times  \frac{1}{ {5}^{74} }

=  {11}^{56}  \times  \frac{1}{ {5}^{18} }

=  \frac{ {11}^{56} }{ {5}^{18} }

8 0
3 years ago
A number cube with faces labeled from 1 to 6 will be rolled once.
kramer

Answer:

\Omega=\{1,2,3,4,5,6\}

A=\{1,2,3,4\}

Step-by-step explanation:

<u>Sample Space</u>

The sample space of a random experience is a set of all the possible outcomes of that experience. It's usually denoted by the letter \Omega.

We have a number cube with all faces labeled from 1 to 6. That cube is to be rolled once. The visible number shown in the cube is recorded as the outcome. The possible outcomes are listed as the sample space below:

\Omega=\{1,2,3,4,5,6\}

Now we are required to give the outcomes for the event of rolling a number less than 5. Let's call A to such event. The set of possible outcomes for A has all the numbers from 1 to 4 as follows

A=\{1,2,3,4\}

3 0
4 years ago
When is a graphing calculator preferable to finding the solutions to an equation?
Natasha2012 [34]

Well, try to find the solution for this…

-0.2x⁵ + 0.04x⁴ - 0.0625x³ - 2x² + 0.3x + 4=0

<span>The answer is 1.33. How would you figure it out without a computer?
In order to find all the roots of a polynome with a grade lower than 2, we need to know at least 1 root (this polynome has grade 5). We can try with the divisors of the constant (4 is the constant), which are: 1,-1,2,-2,4 and -4. But no, none of them verifies the equation! So it will be of hard to find a root. That’s because there are too many fractions, and a fraction can come from a variety of divisions. It’s even more difficult to find a root when there are irrational numbers among the roots (such as the square root of 2, or half a pi, or e). So, if we don’t know any of the roots, we can’t work with the Ruffini rule.</span>

So in this case I suggest to put this in a graphic software:

y=-0.2x⁵ + 0.04x⁴ - 0.0625x³ - 2x² + 0.3x + 4

And there you have the plot. Then you click in “roots” and it will tell you the point: (1.33,0). So that’s how you know 1.33 is the answer.

8 0
3 years ago
Read 2 more answers
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