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Rama09 [41]
3 years ago
11

You want to purchase a new car in 7 years and expect the car to cost ​$77 comma 000. Your bank offers a plan with a guaranteed A

PR of 5.5 % if you make regular monthly deposits. How much should you deposit each month to end up with ​$77 comma 000 in 7 ​years?
Business
1 answer:
Flauer [41]3 years ago
7 0

Answer: $753.58

Explanation: The best way to calculate this is by using a financial calculator. An HP10bII+ is an appropriate financial calculator to use, although other financial calculators should still compute the same answer.

By using a financial calculator to find the answer the following elements are required:

Present Value (PV): the value of money currently that will grow into more money in the future. Because you still have to start saving money to deposit into the bank from the first month, your present value is still $0.

Interest rate (I/YR): the amount, in percentage terms, charged by the bank to you on the value of the money you deposited into the bank. This allows your deposit to grow on a month to month basis. In this case the bank charges an APR of 5.5%.

Number of years (N): the amount of years the money will stay in the bank before it matures. The value will grow over the next 7 years.

Future Value (FV): This is the final amount of a current investment after it has grown in an account that accrues interest over time. In this case it is the expected $77,000 at the end of the 7th year.

All the above elements are computed to find the payment per month (PMT). This is the amount of money you have to deposit into the account every month to receive a total future value of $77,000 after 7 years.

When these figures are inputed into a calculator the following outcome is deduced:

Ensure 12 periods per year (12 shift P/YR on calculator), as deposits are made every month for 12 months every year.

PV = 0

I/YR = 5.5%

N= 84 periods (i.e. 7 years x 12 months per year)

FV = $77.000

∴ PMT = $753.5766 rounded to $753.58 (ignore the minus sign, this only indicates that you are taking money out to deposit into the account monthly)

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Ede4ka [16]

Answer:

The accounting entry for each transaction is given below.

Gibson contributed $10,000 to the business in exchange for capital.

Debit Cash Asset       $10,000

Credit Capital              $10,000

b. Purchased equipment for $5,000 on account.

Debit equipment Asset      $5,000

Credit Payable Liability       $5,000

c. Paid $400 for office supplies.

Debit payable         $400

Credit Cash Asset   $400

d. Earned and received $2,500 cash for service revenue.

Debit Cash Asset    $2,500

Credit Income          $2,500

e. Paid $400 for wages to employees.

Debit Wages expense   $400

Credit Cash Asset          $400

f. Gibson withdrew $1,000 cash

Debit Capital          $1,000

Credit Cash Asset  $1,000

.g. Earned $1,000 for services provided. Customer has not yet paid.

Debit Receivable           $1,000

Credit Service Income   $1,000

h. Paid $1,000 for rent.

Debit Rent expense   $1,000

Credit Cash Asset      $1,000

i. Received a bill for $250 for the monthly utilities. The bill has not yet been paid.

Debit Utility expense     $250

Credit payable                $250

8 0
3 years ago
Matt purchased a 20-year par value bond with an annual coupon rate of 8% compounded semiannually for a price of 1722.25. The cou
finlep [7]

Answer:

(b) 1440

Explanation:

As the coupon rate of 8% is greater than the yield to maturity (YTM) of 6% annually, the bond is selling at a premium. Hence, the bond will be called at the earliest i.e. 15 years.

Coupon = Call Price * Semi-annual coupon rate = X * [0.08 / 2] = X * 0.04

Yield to call = 6% annually = 3% semi-annually

Time = 15 years * 2 = 30

We know that,

Current Price of bond = Coupon * [1 - (1 + YTC)-call date] / YTC + Call Price / (1 + YTC)call date

  • 1,722.25 = [X * 0.04] * [1 - (1 + 0.03)-30] / 0.03 + [X / (1 + 0.03)30]

  • 1,722.25 = [X * 0.04] * 19.60 + [X * 0.41]

  • 1,722.25 = X * [(0.04 * 19.60) + 0.41]

  • 1,722.25 = X * 1.194

  • X = 1,722.25 / 1.194
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4 0
3 years ago
Apex Fitness Club uses straight-line depreciation for a machine costing $23,860, with an estimated four-year life and a $2,400 s
maria [59]

Answer:

1. Book value at end of year 2 = $13,130

2. Depreciation from year 3 for last 3 years = $3,710 each year, that is $11,130 for three years.

Explanation:

As for the provided details, we have:

Cost of machinery = $23,860

Expected life = 4 years

Salvage value = $2,400

Straight line depreciation = \frac{23,860 - 2,400}{4} = 5,365

Under straight line method depreciation remains constant for life of asset.

Book value at end of year 2 = $23,860 - ($5,365 \times 2) = $13,130

Thereafter in the beginning of year 3 the estimate is made to realize that the total remaining life expected is 3 years, with salvage value $2,000

Thus, depreciation from year 3 = \frac{13,130 - 2,000}{3} = 3,710

Therefore, depreciation from year 3 to year 5 = $3,710 each year.

Total depreciation of last 3 years = $3,710 \times 3 = $11,130

3 0
3 years ago
"A customer buys a Brokered CD for $100,000. Upon receipt of his next account statement, the customer sees that the market value
Dmitry_Shevchenko [17]

Answer:

market rates have increased

Explanation:

Bonds as well as brokered CDs are priced depending on the market's interest rates for similar investments. For example, the CD pays a 3% interest, and then the market rate increases to 3.1% (or more), the CD's price will decrease. On the other hand, if the market rates decrease to 2.9% (or less), the CD's price will increase.

8 0
3 years ago
Suppose the revenue from producing​ (and selling) x units of a product is given by Upper R (x )equals 10 x minus . 04 x squared
Volgvan

Answer:

marginal revenue is -6

and production levels 200, 50  

Explanation:

given data

R(x) = 10 x - 0.04 x²  

solution

we have given

R(x) = 10 x - 0.04 x²  

so here R'(x)  is

R'(x) = 10(1) - 0.4 (2x)  

R'(x) = 10 - 0.8 x ....................1

so here at x is 20 marginal revenue will be

R'(20) = 10 - 0.8(20)

R'(20) =  10 - 16

R'(20) = - 6

and

when revenue  is ​$400

R(x) = 400

400 = 10 x - 0.04 x²  

x= 200, 50

7 0
4 years ago
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