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Rama09 [41]
3 years ago
11

You want to purchase a new car in 7 years and expect the car to cost ​$77 comma 000. Your bank offers a plan with a guaranteed A

PR of 5.5 % if you make regular monthly deposits. How much should you deposit each month to end up with ​$77 comma 000 in 7 ​years?
Business
1 answer:
Flauer [41]3 years ago
7 0

Answer: $753.58

Explanation: The best way to calculate this is by using a financial calculator. An HP10bII+ is an appropriate financial calculator to use, although other financial calculators should still compute the same answer.

By using a financial calculator to find the answer the following elements are required:

Present Value (PV): the value of money currently that will grow into more money in the future. Because you still have to start saving money to deposit into the bank from the first month, your present value is still $0.

Interest rate (I/YR): the amount, in percentage terms, charged by the bank to you on the value of the money you deposited into the bank. This allows your deposit to grow on a month to month basis. In this case the bank charges an APR of 5.5%.

Number of years (N): the amount of years the money will stay in the bank before it matures. The value will grow over the next 7 years.

Future Value (FV): This is the final amount of a current investment after it has grown in an account that accrues interest over time. In this case it is the expected $77,000 at the end of the 7th year.

All the above elements are computed to find the payment per month (PMT). This is the amount of money you have to deposit into the account every month to receive a total future value of $77,000 after 7 years.

When these figures are inputed into a calculator the following outcome is deduced:

Ensure 12 periods per year (12 shift P/YR on calculator), as deposits are made every month for 12 months every year.

PV = 0

I/YR = 5.5%

N= 84 periods (i.e. 7 years x 12 months per year)

FV = $77.000

∴ PMT = $753.5766 rounded to $753.58 (ignore the minus sign, this only indicates that you are taking money out to deposit into the account monthly)

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Manufacturing costs from a scraped poor-quality product are $6000 per year. AN investment in an employee training program can re
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Answer:

We see that Prog A will give an annual CF of 75%*$6000 = $4500

Prog B will give annual CF of 95%*$6000 = $5700

Disc Rate Kd = 20%

So PV of Annuity of $1 for 5 yrs with Kd = 20% is 2.9906

So NPV of Prog A = CF0+CF1+ ....+Cf5 = -12000+2.9906*4500 = $1,458

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8 0
3 years ago
Allen Construction purchased a crane 6 years ago for $130,000. They need a crane of this capacity for the next 5 years. Normal o
Korvikt [17]

Answer:

<u>For retaining of Old Machine Equipment</u>

Price of old equipment 3 yrs ago = $130,000

O & M cost per year = $35,000

Using the Cash flow approach

End of year   Cash flow 1   Old equipment

0                            $0            Initial Cash flow

1                         -$35,000     O & M cost per year

2                        -$35,000     O & M cost per year

3                        -$35,000     O & M cost per year

4                        -$35,000     O & M cost per year

5                        -$35,000     O & M cost per year

Hence, Annual worth = Initial cash flow + Annual cost

Annual worth = 0 - $35,000

Annual worth = -$35,000

<u>For buying of new equipment</u>

Cost of buying new crane = $150,000

Market value of old crane = $40,000

Time = 5 years

O & M cost per year = $8,000

Salvage value = $55,000

MARR = 20%

Using the Cash flow approach

End of year   Cash flow 1   New equipment

0                         $110,000    -$150,000 + $40,000

1                         -$8,000     O & M cost per year

2                        -$8,000     O & M cost per year

3                        -$8,000     O & M cost per year

4                        -$8,000     O & M cost per year

5                        $47,000     -$8,000 + $55,000

Annual worth = Initial cash flow + Annual cost + Salvage value

Annual worth = -$110,000(A/P 20%,5) - $8,000 + $55,000(A/P 20%,5)

Annual worth = -$110,000*(0.334) - $8,000 + $55,000*(0.134)

Annual worth = -$36,781.77 - $8,000 + $7,390.88

Annual worth = -$37,908.88

Conclusion: We should retain the old machine as it is more favorable than purchase of new equipment

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