Answer:
I think it is 381.7
Step-by-step explanation:
A= πr(+√h^2+r^2)
The t-test for the two means is appropriate in this situation because women and men are independent samples.
<h3>
What are Independent Samples?</h3>
Independent samples are chosen randomly, ensuring that their results are independent of other observations' values.
The premise that samples are independent underlies many statistical analyses. Others are made to evaluate non-independent sample sets.
The samples of men and women are independent since their results are independent of other observations' values.
The Independent Samples t-Test analyzes the means of two separate groups to see if there is statistical support that the population means values are statistically substantially different.
Learn more about Independent Samples here:
brainly.com/question/14099859
#SPJ4
Well I suppose it depends on how long you have in a day but...
with 30 people you can have it done in about 8hrs
but with 20 people you can have it done in about 12 hours
so my best guess would be anywhere between 20-30 people
Answer/Step-by-step explanation:
Recall the acronym SOHCAHTOA. This is what we would apply as appropriate in each case.
8. θ = 40°
Opp = m
Adj = 20
Thus, apply TOA
Tan (θ) = opp/adj
Plug in the values
Tan (40) = m/20 (equation)
20×Tan(40) = m
m = 16.7820
9. θ = 22°
Hyp = w
Adj = 18
Thus, apply CAH
Cos (θ) = adj/hyp
Plug in the values
Cos 22 = 18/w (equation)
w×cos 22 = 18
w = 18/(cos 22)
w = 19.4136
10. θ = 35°
Hyp = 55
Opp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 35 = x/55 (equation)
55×sin 35 = x
x = 31.5467
11. θ = 33°
Hyp = 19
Adj = x
Thus, apply CAH
Cos θ = adj/hyp
Plug in the values
Cos 33 = x/19 (equation)
19×cos 33 = x
x = 15.9347
12. θ = 17°
Opp = 7
Hyp = x
Thus, apply SOH
Sin θ = opp/hyp
Plug in the values
Sin 17 = 7/x (equation)
x×sin 17 = 7
x = 7/(sin 17)
x = 23.9421
13. θ = 40°
Opp = 15
Adj = x
Thus, apply TOA
Tan θ = opp/adj
Plug in the values
Tan 40 = 15/x (equation)
x×Tan 40 = 15
x = 15/(Tan 40)
x = 17.8763
Let x = Class A
Let y = Class B
Let z = Class C
Equations from problem:
x - 160 = y
2/3x = z
y + 92 = z
Solving through substitution:
2/3x = y + 92
2/3x = (x - 160) + 92
2/3x = x - 68
-1/3x = -68
3(-1/3x) = 3(-68)
-x = -204
x = 204
Now substitute x in the first equation to get y:
204 - 160 = y
44 = y
44 = Class B
There are 44 folded paper cranes in Class B.
