Answer: that the variable can be any number.
Step-by-step explanation:
So we have a linear equation and we end with a relation of the way:
x = x
an example can be if we have:
2*x + 4 = 2*(x + 2)
if you solve that, you will end with a relationship x = x
this means that any value of x will made that equality true.
so x can be any number.
Answer:
You can substitute the x value of coordinate (x,y) in the equation. If the outcome = the y value in the coordinate (x,y), then you have determined it to be on the system of linear equations.
Step-by-step explanation:
Point P has a coordinates: ( Px , Py ).
You can choose which value is easy to substitute. Eighter start with the Py or you could start with the Px. It could save you time if you pick the right one for the job.
If you want to verify if any point is valid in any (linear) equation(s), you can:
a) substitute the x value of coordinate (x,y) in the equation, and if the outcome has the same value as y in the coordinate (x,y), then that point is a valid solution of the (linear) equation.
b) substitute the y value of coordinate (x,y) in the equation, and if the outcome has the same value as x in the coordinate (x,y), then that point is a valid solution of the (linear) equation.
No circle can never be the perfect squares
C
Explanation:
When you plug them in,
(1)x+(0)y=9
x=9
When x is 9, it passes through the point (9,3)
The answer is not infinity.
<span>Consider FBDs of each mass with the direction of motion of m1 as positive </span>
<span>m1*g-T=m1*a </span>
<span>T-m2*g=m2*a </span>
<span>assuming mass less cord and mass less, friction less pulley </span>
<span>the accelerations are equal </span>
<span>a=(T-m2*g)/m2 </span>
<span>m1*g-T=m1*(T-m2*g)/m2 </span>
<span>do some algebra </span>
<span>m1*g-T=m1*T/m2-m1*g </span>
<span>2*m1*g=T*(1+m1/m2) </span>
<span>2*m1*m2*g=T*(m2+m1) </span>
<span>2*m1*m2*g/(m2+m1)=T </span>
<span>now take the limit of T as m1->infinity </span>
<span>T=2*m2*g </span>
<span>this is intuitively correct since the maximum acceleration of m1 is -g, the cord transfers the acceleration to m2, which is being acted on by gravity downward and an upward acceleration of g. Therefore the maximum acceleration of m1 is 2*g upward. </span>
