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torisob [31]
3 years ago
12

Matt has answered 20 over 25 of the questions on a test. what percentage of the test question has Matt answered

Mathematics
2 answers:
anzhelika [568]3 years ago
8 0
80% because 25 goes into 100 4 times and 20 times 4 equals 80.
lyudmila [28]3 years ago
6 0
So,

Matt answered 20 out of 25 questions.
\frac{20}{25}

We need to get the denominator to be 100.  We can do that by multiplying the fraction by a form of 1.
\frac{20}{25} *  \frac{4}{4} =  \frac{80}{100}

From here, it should be easy to see that Matt has answered 80% of his test.
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Please help me out it would make my day!​
nlexa [21]

Answer:

Last option: Square both sides of the equation in step 1 to eliminate the square root.

Step-by-step explanation:

The error is in the process of subtracting 3 from both sides, since +3 is inside the root.

In order to be able to operate with the terms that are inside the root, we need to eliminate the root, and for that we need to square both sides of the equal sign.

6 0
2 years ago
3.5x-81=360 <br> Please help this is due tomorrow
postnew [5]

Answer:

Step-by-step explanation:

so what your gonna do is you are going to add 81 to 360 and then sum it up. after you are going to divide it by 3.5.

This might be wrong but there is always a point where you have to try :)

3 0
2 years ago
Read 2 more answers
Find the surface area of the<br>prism formed by the net.​
pogonyaev

Answer: 1372 Square meters

Step-by-step explanation:

7*14+28*14+7*14+7*28+14*28+7*28=1372

4 0
3 years ago
If y= 3x + 6, what is the minimum value of (x^3)(y)?
Rainbow [258]

Answer:

Given the statement: if y =3x+6.

Find the minimum value of (x^3)(y)

Let f(x) = (x^3)(y)

Substitute the value of y ;

f(x)=(x^3)(3x+6)

Distribute the terms;

f(x)= 3x^4 + 6x^3

The derivative value of f(x) with respect to x.

\frac{df}{dx} =\frac{d}{dx}(3x^4+6x^3)

Using \frac{d}{dx}(x^n) = nx^{n-1}

we have;

\frac{df}{dx} =(12x^3+18x^2)

Set \frac{df}{dx} = 0

then;

(12x^3+18x^2) =0

6x^2(2x + 3) = 0

By zero product property;

6x^2=0   and 2x + 3 = 0

⇒ x=0 and x = -\frac{3}{2} = -1.5

then;

at x = 0

f(0) = 0

and  

x = -1.5

f(-1.5) = 3(-1.5)^4 + 6(-1.5)^3 = 15.1875-20.25 = -5.0625


Hence the minimum value of (x^3)(y) is, -5.0625






3 0
3 years ago
In the diagram, AC=BD. Show that AB=CD
Debora [2.8K]
I believe you just have to draw 2 little lines in between AB and CD.
8 0
3 years ago
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