<h2>Answer</h2>
0.43
<h2>Explanation</h2>
Remember that 
Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so 
. Now, the sum of all frequencies will be the sum of all the 10th graders, so 
. Let's replace the values:
And rounded to the nearest hundredth:
<h3>
Answer: Yes</h3>
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Explanation
The ratio 8:10 simplifies to 4:5 when you divide both parts by 2.
The ratio 16:20 simplifies to 4:5 when you divide both parts by 4
Therefore the two ratios 8:10 and 16:20 are both equal 4:5, so they are equal to one another.
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Put another way,
(8 large)/(10 small) = (16 large)/(20 small)
8/10 = 16/20
8*20 = 10*16 ... cross multiply
160 = 160
We get a true equation, so the first equation is true as well.
This shows the ratios are equivalent.
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Or you could have...
(8 large)/(16 large) = (10 small)/(20 small)
8/16 = 10/20
8*20 = 16*10
160 = 160
We get the same conclusion as before.
Answer:
(0,-1)
You can guess and check to see what gives you the answer
The z scores corresponding to the mean weight of a rotten apple relative to the apples from either orchard are, respectively,
The mean for the standard normal distribution is 0, which means that z scores closer to 0 represent data points that are more likely to occur. Therefore it's reasonable to believe that rotten apples occur more often in shipments from Zippy's.
I am assuming you wrote the problem wrong. Is it a^2?
A^2 -4A-21=0
(A-7)(A+3)=0
A=7 A=-3, ignore the negative number because it doesn't make sense if you plug in for a.
length=a+3=7+3=10
Width=7=a
