Ask question

Ask question

All categories

Alex_Xolod [135]

2 years ago

15

Which of the following is not a valid reason for a dealership to offer

2 answers:

kykrilka [37]2 years ago

8 0

Answer:

d because it is the best answer

to use

Step-by-step explanation:

BARSIC [14]2 years ago

6 0

Answer:

Can also be Offset the cost of gasoline

Step-by-step explanation:

AP3X

You might be interested in

Which line is parallel to the line

UkoKoshka [18]

I think its b , but iam not sure

5 0

2 years ago

HELP ME WITH MY MATH ASSIGNMENT, WILL GIVE ANYTHING, DUE TOMORROW! :(

nataly862011 [7]

Answer:

Answer is 225.

We have to find the sum of 15 terms of the series

sigma 1 to 15 (2n-1)

This can be split as per summation terms as

sigma 2n - sigma 1

sigma 2n can again be simplified by taking 2 outside

sigma 2n= 2 times sum of natural numbers of 1 to 15

= 2(15)(16)/2= 240

sigma 1= 1+1+...15 times= 15

Hence final answer is

= 2 times sigma n - (n) = 240-15 = 225.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I need help!!! please help me out as quick as possible

Alenkasestr [34]

Answer:

D) 262,144

Step-by-step explanation:

The given sequence is given explicitly as:

$A_n = {4}^{n - 1}$

We want to find the tenth term of this sequence.

We substitute n=10 to get:

$A_ {10}= {4}^{10 - 1}$

Simplify the exponent

$A_ {10}= {4}^{9}$

Simplify the power

$A_ {10}= 262144$

Therefore the 10th term is 262,144

3 0

2 years ago

Mr. Jones' other friend Ms. O'Neill has "x" meters of fencing, what is the maximum area in square meters she can have?

Alexus [3.1K]

Answer:

$Max\ Area = \frac{x^2}{16}$

Step-by-step explanation:

Given

$P = x$ ---- the perimeter of fencing

Required

The maximum area

Let

$L \to Length$

$W \to Width$

So, we have:

$P = 2(L + W)$

This gives:

$2(L + W) = x$

Divide by 2

$L + W = \frac{x}{2}$

Make L the subject

$L = \frac{x}{2} - W$

The area (A) of the fence is:

$A = L * W$

Substitute $L = \frac{x}{2} - W$

$A = (\frac{x}{2} - W) * W$

Open bracket

$A = \frac{x}{2}W - W^2$

Differentiate with respect to W

$A' = \frac{x}{2} - 2W$

Set to 0

$\frac{x}{2} - 2W = 0$

Solve for 2W

$2W = \frac{x}{2}$

Solve for W

$W = \frac{x}{4}$

Recall that:

$L = \frac{x}{2} - W$

$L = \frac{x}{2} - \frac{x}{4}$

$L = \frac{2x- x}{4}$

$L = \frac{x}{4}$

So, the maximum area is:

$A = L * W$

$A = \frac{x}{4}*\frac{x}{4}$

$Max\ Area = \frac{x^2}{16}$

8 0

2 years ago

A bag has fifteen marbles in it Six of them are green, one of them is red, five of them are yellow, and three of them are blue.

yarga [219]

Answer:

A

Step-by-step explanation:

Subtract total amount of marbles by the amount of yellow marbles. You should get 10.

Divide 10 by the total amount of marbles

10/15

You should get 0.6666667

Round

5 0

3 years ago