Answer:
7/10 hours
Step-by-step explanation:
her first assignment took 1/2 hour
her second assignment took 1/5 hour
so in total she took 1/2 + 1/5
we need to find a common denominator
the lcm(2,5)=10
so multiply 1/2 by 5/5 to obtain 5/10
multiply 1/5 by 2/2 to obtain 2/10
5/10 + 2/10 = 7/10
The cubic feet of space that is in the subway car is the volume of the subway car which is 5,502.
<h3>How many cubic feet of space are there in a subway car?</h3>
The shape of a subway car is in the form of a rectangular prism. In order to determine the cubic feet of space, the volume of the car has to be determined. The formula for the volume of a rectangular prism would be used.
Volume = width x height x length
12 x 51 x 8.5 = 5205
Here is the complete question:
The floor of an NYC subway car measures approximately 51 feet by 8.5 feet. The height of the NYC subway car measures approximately 12 feet. How many cubic feet of space are there in a subway car?
To learn more about the volume of a cuboid, please check: brainly.com/question/26406747
Answer:
3t - 16
Step-by-step explanation:
(18/12 t-8)*2
First simplify inside the parentheses
(3/2 t -8)*2
Then multiply
3/2t *2 -8*2
3t - 16
The next number in the sequence is 36.
Starting from 1, the number increases by 3, 1 + 3 = 4. But the next number, the number it's being increased by increases by 2. 3 + 2 = 5, 4 + 5 = 9. And again, 5 + 2 = 7, 7 + 9 = 16. And again. 7 + 2 = 9, 16 + 9 = 25. Therefore, it is increased to + 11, and the next number is 36.
I hope this helped, and you have a great day!
<h3><u>
Answer:</u></h3>
Option: D
Horizontal stretching.
<h3><u>
Step-by-step explanation:</u></h3>
We have to find the effect on the graph of the function f(x)=2x when it is replaced by f(0.5 x).
We know that when a parent function f(x) is replaced by f(kx) then either the graph is stretched horizontally or shrinked horizontally.
if k>1 then the graph is shrinked horizontally.
if k<1 then the graph is stretched horizontally.
Hence here k=0.5<1 so the graph of the function is stretched horizontally.
