The number of gallons of water in the tank at t=10 is
... W(10) = 160,000 -10(8000 -10) = 80100
The number of gallons of water in the tank at t=10.5 is
... W(10.5) = 160,000 -10.5(8000 -10.5) = 76110.25
The rate of change over the interval is
... (W(10.5) - W(10))/(10.5 - 10) = (76110.25 - 80100)/(0.5) = -7979.5
The average rate of change in the number of gallons of water in the tank over the interval is -7979.5 gal/min.
The sign is negative, so the amount of water is decreasing.
Answer:
10.7cm
Step-by-step explanation:
x^2= 115
x = √115
x = 10.7
Answer:
X+6
Step-by-step explanation:
Combined like terms.
The empty jug weighs 0.75 lb
With the 3c, the total weighs 2.25 lb. That means:
3c + empty jug = 3c + 0.75 = 2.25
3c = 2.25 - 0.75
3c = 1.5
and 1c = 0.5 (so c is a constant -or the slope-)
Then the equation is:
y = 0.5x + 0.75