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3 years ago

Find the product and fill the blanks to write in standard complex number form. x^2+2x+10=0

Mathematics

1 answer:

iren2701 [21]3 years ago

3 0

Answer:

Have you tried the quadratic formula? you can look up the quadratic equation and plug in the, a=1 b=2 and c=10

Step-by-step explanation:

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Please help solve this equation. Show all steps please. No links or files.

maksim [4K]

Answer:

See below

Step-by-step explanation:

c = (a^2 + 3b) / 4 multiply both sides by 4

4c = a^2 + 3b subtract a^2 from both sides

4c - a^2 = 3b now divide both sides by 3

(4c-a^2) / 3 = b

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2 years ago

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alexgriva [62]

The slope of the line is: y= 2x+2

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3 years ago

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3 years ago

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3 years ago

The fraction of defective integrated circuits produced in a photolithography process is being studied. A random sample of 300 ci

Olenka [21]

Answer:

The correct answer is

(0.0128, 0.0532)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

Z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$

For this problem, we have that:

In a random sample of 300 circuits, 10 are defective. This means that $n = 300$ and $\pi = \frac{10}{300} = 0.033$

Calculate a 95% two-sided confidence interval on the fraction of defective circuits produced by this particular tool.

So $\alpha$ = 0.05, z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 - 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0128$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{300}} = 0.033 + 1.96\sqrt{\frac{0.033*0.967}{300}} = 0.0532$

The correct answer is

(0.0128, 0.0532)

4 0

3 years ago