Answer:
Step-by-step explanation:
Answer:
Quadratic
Step-by-step explanation:
2.625 is 21/8 into a decimal
Answer:
the cost of running the boarding
house for 600 students is N61,000
Step-by-step explanation:
Let C represents cost
K1 represents first constant
K2 represents second constant
C= k1+k2n
3500 = k1 + 25 k2............. Eqn(1)
6000= k1 + 50 k2 .............. Eqn(2)
Subtract eqn(1) from eqn(2)
2500= 25k2
K2= 2500/25
K2= 100
To get k1 from eqn(1)
3500 = k1 + 25 k2
Substitute the value of k2
3500 = k1 + 25 (100)
3500= k1 +2500
K1= 3500- 2500
K1= 1000
The equation connecting them;
C= 1000+ 100n
The cost of running the boarding
house for 600 students is
n= 600
C= 1000+ 100(600)
C= 1000+60000
C= N 61,0000
The value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
According to the given question.
We have some linear equations.
xy = 4n + 3
yz = 2n - 7
and
xz = 20
Since, y is between x and z. Which means y, x and z are collinear points.
Therefore,
xy + yz = xz
⇒ 4n + 3 + 2n - 7 = 20
⇒ 6n -4 = 20
⇒ 6n = 20 + 4
⇒ 6n = 24
⇒ n = 24/6
⇒ n = 4
Therefore,
yz = 2n - 7 = 2(4) - 7 = 8- 7 = 1
Hence, the value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
Find out more information about collinear points here:
brainly.com/question/1593959
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