Question

Use the student's t distribution to find tc for a 0.95 confidence level when the sample is 17. (round your answer to three decimal places.)

Answer 1

Answer:

The t critical value at 0.05 significance level for $df=n-1=17-1=16$ is:

$t_{critical}=\pm2.120$

Step-by-step explanation:

We are given confidence level =0.95

$n=17$

Significance level = 1 - confidence level

                              = 1 - 0.95

                               = 0. 05

Degrees of freedom = n - 1 = 17 - 1 = 16

Therefore, using the t distribution table, the t critical values are:

$t_{critical} = \pm 2.120$