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3 years ago

X^2-5x+6=0 quadratic form

Mathematics

2 answers:

Olenka [21]3 years ago

7 0

Answer:

x = 3,2

Step-by-step explanation:

solve for x by finding a,b,c and then apply the quadratic formula.

Vesna [10]3 years ago

6 0

Answer:x

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Explanation:

The quadratic formula is:

⇒

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√

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for a quadratic of the form

We have

, and

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√

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(

)

(

)

(

)

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√

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√

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Hence,

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and

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I'm not sure why you wanted to use the quadratic formula, but you could just factor the quadratic:

(

)

(

)

→

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and

→

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Step-by-step explanation:

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Sixteen is the same as one and two-tenths times a number added to negative 8

Archy [21]

Answer:

Step-by-step explanation:

16=1 2/10R + -8

16+8= 12/10R

24=12/10R

R=20

3 0

3 years ago

Read 2 more answers

Suppose that the probability that any particle emitted by a radioactive material will penetrate a certain shield is 0.01. If 10

AnnyKZ [126]

Answer:

a)P=0.42

b) $n\geq 297$

Step-by-step explanation:

We have a binomial distribution, since the result of each experiment admits only two categories (success and failure) and the value of both possibilities is constant in all experiments. The probability of getting k successes in n trials is given by:

$P=\begin{pmatrix}n\\ k\end{pmatrix} p^k(1-p)^{n-k}=\frac{n!}{k!(n!-k!)}p^k(1-p)^{n-k}$

a) we have k=2, n=10 and p=0.01:

$P=\frac{10!}{2!(10!-2!)}0.01^2(1-0.01)^{10-2}\\P=\frac{10!}{2!*8!}0.01^2(0.99)^{8}\\P=45*0.01^2(0.99)^8=0.42$

b) We have, $1-(1-p)^n=P$ , Here P is the probability that at least one particle will penetrate the shield, this probabity has to be equal or greater than 0.95. Therefore, this will be equal to subtract from the total probability, the probability that the particles do not penetrate raised to the total number of particles.