Identify the oblique asymptote of f(x) = quantity x plus 4 over quantity 3 x squared plus 5 x minus 2.
2 answers:
3x² + 5x - 2 = 0
3x² + 6x - x - 2 = 0
3x(x) + 3x(2) - 1(x) - 1(2) = 0
3x(x + 2) - 1(x + 2) = 0
(3x - 1)(x + 2) = 0
3x - 1 = 0 or x + 2 = 0
+ 1 + 1 - 2 - 2
3x = 1 or x = -2
3 3 1 1
x = ¹/₃ or x = -2
f(x) = 3x² + 5x - 2
f(¹/₃) = 3(¹/₃)² + 5(¹/₃) - 2
f(¹/₃) = 3(¹/₉) + 1²/₃ - 2
f(¹/₃) = ¹/₃ - ¹/₃
f(¹/₃) = 0
(x, f(x)) = (¹/₃, 0)
f(x) = 3x² + 5x - 2
f(-2) = 3(-2)² + 5(-2) - 2
f(-2) = 3(4) - 10 - 2
f(-2) = 12 - 12
f(-2) = 0
(x, f(x)) = (-2, 0)
Vertical Asymptotes: ¹/₃ or -2
Horizontal Asymptotes: 0
Oblique Asymptote: No Asymptotes
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Answer:
The diameter of can is<u> 48 inches</u>.
Step-by-step explanation:
Given:
Volume of can = 6068 inches.
And height(h) = 3.3 inches.
Now, to find the diameter.
Diameter = 2 × radius
Let radius be
So, by putting the formula of volume we get the radius:
(taking the value of π=3.14)
<em>Dividing both sides by 10.362 we get:</em>
<em>Using square root on both sides we get</em>:
<em>Radius = 24.199 inches.</em>
Then, we get the diameter:
Diameter = 2 × radius
Diameter = 2 × 24.199 = 48.398 inches.
Diameter = 48 inches (rounding to nearest, inch as in the place of tenth it is 3 which is less than 5.)
Therefore, the diameter of can is 48 inches.