how do you find the surface area of a rectangular box with length 10 inches,width 6 inches and height 4 inches
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In degrees: 3π/4 radians = 135°
Angle of x=135° is in the 2nd Quadrant and has negative cos x values and positive sin x values.
cos 135° = cos ( 90° + 45°)= - sin 45° =
sin 135° = sin ( 90° + 45° ) = cos 45° =
. You can also see the graph in the attachment.
Angle of x=135° is in the 2nd Quadrant and has negative cos x values and positive sin x values.
cos 135° = cos ( 90° + 45°)= - sin 45° =
sin 135° = sin ( 90° + 45° ) = cos 45° =