Equation of this line is K = -2J + 28
<u>Step-by-step explanation:</u>
Step 1:
The equation can be written in slope intercept form which is y = mx + b
Step 2:
Calculate slope of the line, m = (y2 - y1)/(x2 - x1)
⇒ m = (24 - 20)/(2 - 4) = 4/-2) = -2
Step 3:
Find y-intercept of the line
⇒ b = 28
Step 4:
Substitute values in the equation
⇒ K = -2J + 28
Given plane Π : f(x,y,z) = 4x+3y-z = -1
Need to find point P on Π that is closest to the origin O=(0,0,0).
Solution:
First step: check if O is on the plane Π : f(0,0,0)=0 ≠ -1 => O is not on Π
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e.
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane Π , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane Π
Answer: P(-2/13, -3/26, 1/26) is the point on Π closest to the origin.
49 unit because and any subsequent words was ignored because we limit queries to 32 words.
Answer:
The answer would be B
Step-by-step explanation:
All you have to do is multiply to see what its multiplied by to get the sizes of T Which is all by 4 so your answer is B
