All categories

4 years ago

22/30 in lowest terms

Mathematics

2 answers:

Oksana_A [137]4 years ago

6 0

2 goes into 22 and 30 so divide 22 by 2 and 30 by 2 so that will equal 11/15

Arada [10]4 years ago

3 0

11/15, you would just divide 22/30 in half and that's as far as it can go.

You might be interested in

The area of a rectangle is 40 square feet. What could be the perimeter of the rectangle? how is this problem solved.

schepotkina [342]

A possible perimeter for the rectangle would be 28

Area=L x W

40/10=4

Width=4, Length=10

Perimeter=L+L+W+W

4+4+10+10=28

4 0

3 years ago

Read 2 more answers

Please explain how to do this i am lost

mixas84 [53]

Answer: y = 7x - 6

Step-by-step explanation:

7 = m (slope)

-6 = y-intercept

8 0

3 years ago

Read 2 more answers

1: 18 is __ % of 30

Zigmanuir [339]

Answer:

1. 60%

2. 70

3. 8%

Step-by-step explanation:

I attached pictures to show my work (sorry if they’re a bit messy)!

4 0

2 years ago

*30 POINTS* HELP FOR BRAINLIEST

Marta_Voda [28]

Answer:

Step-by-step explanation:

f(x) =x^2 - 6x + 21

f(xl =0

Answer:

substitute 0 for x

f(0) = 0^2 - 6(0) + 21

0. = 0 - 0 + 21

0. = 21

6 0

3 years ago

HELPP!!what is the answer to this picture above^

nasty-shy [4]

Answer:

$\fbox{ \fbox { \sf{Distance = \sf{15 \: units}}}}$

${ \fbox { \fbox { \sf{Midpoint = { \sf{ \: (12 \: , \: 10.5)}}}}}}$

Step-by-step explanation:

$\star{ \: \sf { \: Let \: the \: points \: be \: A \: and \: B}}$

$\star { \sf{Let \: A(6 \:, 6) \: be \: (x1 ,\: y1) \: and \: B(18 ,\: 15) \: be \: (x2 \:, y2)}}$

$\underline{ \underline{ \tt{Finding \: the \: distance}}}$

$\boxed{ \sf{Distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(18 - 6)}^{2} + {(15 - 6)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{ {(12)}^{2} + {(9)}^{2} } }}$

$\mapsto{ \sf{Distance = \sqrt{144 + 81}}}$

$\mapsto{ \sf{Distance = \sqrt{225} }}$

$\mapsto{ \sf{Distance = \sqrt{ {15}^{2} } }}$

$\mapsto{ \boxed{\sf{Distance = 15 \: units}}}$

$\underline{ \underline {\tt{Finding \: the \: Midpoint}}}$

$\boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} \: , \: \frac{y1 + y2}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{6 + 18}{2} \: , \: \frac{6 + 15}{2} )}}$

$\mapsto{ \sf{Midpoint = ( \frac{24}{2} \: , \: \frac{21}{2} )}}$

$\mapsto{ \boxed{ \sf{Midpoint = (12 \: , \: 10.5)}}}$

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

3 0

3 years ago