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Sloan [31]
3 years ago
10

Is 3.774447444744474447444 a rational number

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0
No it is an irrational number because it is a decimal with repeating numbers.
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12a^3b^2 +18a²b^2 – 12ab^2<br> Factor completely
AleksAgata [21]

The factorization of 12a^3b^2 +18a²b^2 – 12ab^2 is 6 a b^{2}(a+2)(2 a-1)

<u>Solution:</u>

Given, expression is 12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

We have to factorize the given expression completely.

Now, take the expression

12 a^{3} b^{2}+18 a^{2} b^{2}-12 a b^{2}

Taking b^2 as common term,

b^{2}\left(12 a^{3}+18 a^{2}-12 a\right)

Taking "a" as common term,

b^{2}\left(a\left(12 a^{2}+18 a-12\right)\right)

Taking "6" as common term,

b^{2}\left(a\left(6\left(2 a^{2}+3 a-2\right)\right)\right)

Splitting "3a" as "4a - a" we get,

b^{2}\left(a\left(6\left(2 a^{2}+4 a-a-2\right)\right)\right)

\begin{array}{l}{b^{2}(a(6(2 a(a+2)-1(a+2))))} \\\\ {b^{2}(a(6((a+2) \times(2 a-1))))} \\\\ {6 a b^{2}(a+2)(2 a-1)}\end{array}

Hence, the factored form of given expression is 6 a b^{2}(a+2)(2 a-1)

4 0
3 years ago
What is the greatest prime you must consider to test if 5628 is prime
Brut [27]
I believe the answer to this would be 268
8 0
3 years ago
Is a line segment a defined or undefined term?
Savatey [412]
<span>Line Segment: A line segment is just part of a line. Remember above when I said that lines are indefinite, and that they keep going and going? Line segments stop somewhere in both directions.</span><span>
Therefore its defined.

</span>
3 0
3 years ago
Can someone please check my answers to see if they are correct??!!!
vekshin1
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4 0
3 years ago
Read 2 more answers
A company has a fleet of 200 vehicles. On average, 50 vehicles per year experience property damage. What is the probability that
ICE Princess25 [194]

Answer:

The probability is \frac{1}{4} or 25%

Step-by-step explanation:

The question states the total number of vehicles, as well as the number of damaged vehicles on a yearly basis. If 50 vehicles in every 200 vehicles per year are damaged, then we can obtain:

Probability of a damaged vehicle in any given year = \frac{Number of Damaged Vehicles}{Total Number of Vehicles}

= \frac{50}{200} = \frac{1}{4} or 25%

4 0
3 years ago
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