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3 years ago

What are the solutions of x^2-2x+5=0

Mathematics

1 answer:

Damm [24]3 years ago

3 0

Answer:

1 + 2i and 1 – 2i

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A manufacturer has invested $120,000 in a new product and wants to set a price to earn a $80,000 profit. The variable cost per u

Misha Larkins [42]

Answer: 500

Step-by-step explanation:

The remainder of the question is:

How many units does the company need to sell to reach the target profit?

The required sales to break even will be calculated as:

= (Fixed cost + Required profit) / ( Price per unit - Variable cost)

= (120000 - 80000) / (100 - 20)

= 40000/80

= 500

The company needs to sell 500 units.

6 0

3 years ago

Round the number 13.734 to the nearest whole<br>number (positive integer).

loris [4]

Answer: 14
The number to the right of the decimal point is either 5 or greater than that, so the 13 is increased by 1 which results in 14.

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3 years ago

Find the area and perimeter of the

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3 years ago

Which three-dimensional object is formed when the shape is rotated about the axis as shown?

never [62]

C the sphere i think

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4 years ago

Find a formula for Y(t) with Y(0)=1 and draw its graph. What is Y\infty?

tino4ka555 [31]

Answer:

$(a)\ y(t)\ =\ -2e^{-2t}+3$

$(b)\ y(t)\ =\ 4e^{-2t}-3$

Step-by-step explanation:

(a) Given differential equation is

Y'+2Y=6

=>(D+2)y = 6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

$y_c(t)\ =\ C.e^{-2t}$

To find the particular integral, we will write

$y_p(t)\ =\ \dfrac{6}{D+2}$

$=\ \dfrac{6.e^{0.t}}{D+2}$

$=\ \dfrac{6}{0+2}$

= 3

so, the total solution can be given by

$y_(t)\ =\ C.F+P.I$

$=\ C.e^{-2t}\ +\ 3$

$y_(0)=C.e^{-2.0}\ +\ 3$

but according to question

1 = C +3

=> C = -2

So, the complete solution can be given by

$y_(t)\ =\ -2.e^{-2.t}\ +\ 3$

(b) Given differential equation is

Y'+2Y=-6

=>(D+2)y = -6

To find the complementary function, we will write

D+2=0

=> D = -2

So, the complementary function can be given by

$y_c(t)\ =\ C.e^{-2t}$

To find the particular integral, we will write

$y_p(t)\ =\ \dfrac{-6}{D+2}$

$=\ \dfrac{-6.e^{0.t}}{D+2}$

$=\ \dfrac{-6}{0+2}$

= -3

so, the total solution can be given by

$y_(t)\ =\ C.F+P.I$

$=\ C.e^{-2t}\ -\ 3$

$y_(0)\ =C.e^{-2.0}\ -\ 3$

but according to question

1 = C -3

=> C = 4

So, the complete solution can be given by

$y_(t)\ =\ 4.e^{-2.t}\ -3$

4 0

3 years ago