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3 years ago

15 points please IF NOT YOUR COMMENT WOULD BE REPORTED ALSO YOUR ACCOUNT pls thank you ☺️

Mathematics

1 answer:

HACTEHA [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Given

$\sqrt{qrv+11}$ = 30 ( square both sides to clear the radical )

qrv + 11 = 900 ( subtract 11 from both sides )

qrv = 889 ( divide both sides by rv )

q = $\frac{889}{rv}$ → A

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Consider this expression.

xxTIMURxx [149]

Answer:

hope this helped you

please mark as the brainliest (ㆁωㆁ)

8 0

2 years ago

Point A is located at (-4,\ 9)(−4, 9) on the coordinate plane. Point B is located at (-4,\ -7)(−4, −7). What is the distance be

galben [10]

Answer:

AB = 16 units

Step-by-step explanation:

Given the coordinate (-4, 9) and (-4, -7)

Using the formula for calculating the distance between two points

AB = √(x2-x1)²+(y2-y1)²

AB =√(-7-9)²+(-4+4)²

AB = √(-16)²+0²

AB = √16²

AB = 16 units

Hence the distance between Point A and Point B is 16 units

8 0

3 years ago

If a= (-1,-3) and b= (11,8), what is the length of AB?

Margarita [4]

Answer:

4.80 units (3 s.f.)

Step-by-step explanation:

$distance \: formula \\ = \sqrt{(x1 - x2)^{2}+ (y1 - y2)^{2} }$

Hence, length of AB

= √(11+1)^2 - (8+3)^2

= √ 12^2 -11^2

= √ 23

= 4.80 units (3 s.f.)

6 0

3 years ago

30 POINTS!

Goshia [24]

Answer:

The correct answare would be 3.54 x 10^22 N

7 0

2 years ago

Solve for A ? <br><br> Anyone willing to help me :)

GrogVix [38]

Answer:

Step-by-step explanation:

Use the cosine law:

$BC^2=AB^2+AC^2-2(AB)(AC)\cos(\angle A)$

We have:

$BC=a\\\\AB=4\\\\AC=3\\\\m\angle A=32^o\to\cos32^o\approx0.848$

Substitute:

$a^2=4^2+3^2-2(4)(3)(0.848)\\\\a^2=16+9-20.352\\\\a^2=4.648\to a=\sqrt{4.648}\\\\a\approx2.2$

5 0

2 years ago