Answer:
2 gallons
since each pitcher holds 2 quarts of water and 4 quarts= 1 gallon, Desta poured 2 gallons of water into her cooler
The rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
<h3>Howe to solve for the rate of the plane and wind</h3>
In 7 hours the kilometer traveled = 4340
P + W = 4340/7
= 620
P-W = 3120/3 hours
= 1040
2p = 1040 + 620
= 1660
p =830
W = 1040 - 830
= 210
Hence the rate of the wind is given to be 210 the rate of the plane in mid air is given as 830
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Answer:
(g o f)(x) = 
(not simplified)
Step-by-step explanation:
(g o f)(x) = g(f(x))
g(x) = 
f(x) = 
g(f(-5)) = g(
= 
= 
g(-170) = 
=
Answer:
242
Step-by-step explanation:
Simplify the following:
11 ((9^2 - 5^2)/2^2 + 8)
Hint: | Evaluate 2^2.
2^2 = 4:
11 ((9^2 - 5^2)/4 + 8)
Hint: | Evaluate 5^2.
5^2 = 25:
11 ((9^2 - 25)/4 + 8)
Hint: | Evaluate 9^2.
9^2 = 81:
11 ((81 - 25)/4 + 8)
Hint: | Subtract 25 from 81.
| 7 | 11
| 8 | 1
- | 2 | 5
| 5 | 6:
11 (56/4 + 8)
Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.
The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:
11 (14 + 8)
Hint: | Evaluate 14 + 8 using long addition.
| 1 |
| 1 | 4
+ | | 8
| 2 | 2:
11×22
Hint: | Multiply 11 and 22 together.
| 2 | 2
× | 1 | 1
| 2 | 2
2 | 2 | 0
2 | 4 | 2:
Answer: 242
