Yes because the median and range are not a function of the totality of the sample set, the median is just value that is halfway of the set.

Hope this helps :)
~Davinia.

5 0

3 years ago

For each sequence write an explicit formula 96,48,24,12,6

STALIN [3.7K]

$a_1=96;\ a_2=48;\ a_3=24;\ a_4=12;\ a_5=6\\\\a_1=a_2:2\to96:2=48\\a_2=a_3:2\to48:2=24\\a_3=a_2:2\to24:2=12\\a_4=a_3:2\to12:2=6\\\\therefore\\\\a_n=96:2^{n-1}=\frac {96}{2^{n-1}}\\\\check:\\a_1=\frac{96}{2^{1-1}}=\frac{96}{1^0}=96\\a_2=\frac{96}{2^{2-1}}=\frac{96}{2^1}=\frac{96}{2}=48\\a_3=\frac{96}{2^{3-1}}=\frac{96}{2^2}=\frac{96}{4}=24\\\vdots$

8 0

3 years ago

in triunghiul isoscel ABC, AB=AC=36cm, m(BAC)=45°, iar BE perpendicular pe AC, E apartine (AC). Calculati Aria ABC, BE

melisa1 [442]

when given SAS, the area (A) of the triangle = (side1 · sin θ · side2)/2

A = (36 · sin 45° · 36)/2

= (36² · √2)/4

= 9 · 36 · √2

= 324√2

≈ 458.2

4 0

3 years ago