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lozanna [386]
3 years ago
10

Jaylon spent $21.60 of the $80 he got for his birthday. What percent of his money did he spend? Oh

Mathematics
2 answers:
Anika [276]3 years ago
5 0

Answer:

27%

Step-by-step explanation:

Jaylon spent 27% of his birthday money.

ioda3 years ago
5 0

Answer:

27%

Step-by-step explanation:

To find the percent spent, take the amount spent and put it over the total

21.60 /80

.27

Multiply by 100% to put in percent form

27%

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4 - 5/2 * (1/10x) = 1 what is the value of x
Inga [223]

4 - 5 / 2 * (1/10x) = 1\\

The first step is to identify the order in which the equation must be solved, by following PEMDAS (you might know it as BEDMAS):

Parenthesis (or Brackets)

Exponents

Multiplication and Division

Addition and Subtraction

My advice would be to add parenthesis, following these rules, if you are not very good at finding them immediately by sight.

So:

4 - 5 / 2 * (\frac{1}{10x})  = 1\\\\4 - [(5/2)*(\frac{1}{10x})]=1\\\\4-(2.5*\frac{1}{10x})=1\\\\4-\frac{2.5}{10x}-1=0\\3-\frac{x}{4}=0\\\frac{x}{4}=3\\x=3*4\\x=12

We check our answer:

x=12\\4 - [(5 / 2) * (1/10)*(x)] = 1\\4 - [(5 / 2) * (\frac{1}{10}) * (12))] = 1\\4 - [2.5 * (\frac{1}{10})*12] = 1\\4 - [(\frac{2.5}{10})*12] = 1\\4 - [(\frac{1}{4})*12] = 1\\4 - 3 = 1\\1=1

We are right!

So, x=12.

6 0
3 years ago
Describe how to transform the quantity of the fifth root of x to the seventh power, to the third powerinto an expression with a
geniusboy [140]
(\sqrt[5]{x^{7}})^{3}=(x^{\frac{7}{5}})^{3}=x^{\frac{7\cdot3}{5}}=x^{\frac{21}{5}}

The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.
7 0
3 years ago
What is the area of a triangle with a base of 6mm and a height of 9mm
baherus [9]
Areaa= 0.5 b h
= 0.5 x 9 x 6 = 27 mm
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SCUBA diving set
lys-0071 [83]

Answer:

Step-by-step explanation:

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Snorkel, mask, and flippers Slope intercept form: y = 2x + 10

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A baker makes 24 cookies in 4 hours. At this rate,
Vadim26 [7]

Answer:

The baker will make 60 cookies in 10 hours.

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