Answer:
Solution given:

now
f(x)+g(x)=
....(1)
now
factoring x²+6x-40
we get
x²+10x-4x-40
x(x+10)-4(x+10)
(x+10)(x-4)
now substituting in equation 1 ,we get
f(x)+g(x)=
taking l.c.m
=
=now
opening bracket

=
So
answer is :
B. 
The function is undefined where the denominator is zero. The value x=2 must be excluded from the domain.
The 2nd selection, "all real numbers except 2", is appropriate.
Answer:
3.50h+10
Step-by-step explanation:
H is hours
Answer:
x = 3 and y = 1
Step-by-step explanation:
Given equations
y=3x-8 and y=4-x
We will substitute y from second equation in the first and get:
4-x = 3x-8 first we will add (+x) to both sides and get
4-x+x = 3x+x-8 => 4 = 4x-8 now we will add (+8) to the both sides and get
4+8 = 4x-8+8 => 12 = 4x now we will change the sides of equation and get
4x = 12 => x = 12/4 = 3 => x=3 now we will replace x=3 in the second equation
y= 4-x = 4-3=1 => y=1
Finally we have (x , y) = ( 3 , 1)
God with you!!!
69.6 is the answer to ur question