Answer:
400 lb of salt
Step-by-step explanation:
Let us assume the water flows into the rank for x minutes.
There is an initial of 1000 gallons of water in the tank and water flows in through one pipe at 4 gal/min and through another pipe at 6 gal/min. In x minute, the amount of water in the tank = 1000 + 4x + 6x = 1000 + 10x
Water flows out at 5 gal/min, therefore in x minute the amount of water in the tank = 1000 + 10x - 5x = 1000 + 5x
The tank begins to overflow when it is full (has reached 1500 gallons). Therefore:
1500 = 1000 + 5x
5x = 1500 - 1000
5x = 500
x = 100 minutes.
1/2 lb salt per gallon flows into the tank at 4 gal/min and 1/3 lb of salt is flowing in at 6 gal/min, in 100 min the amount of salt that entered the tank = 4 gal/min × 100 min × 1/2 lb/gal + 6 gal/min × 100 min × 1/3 lb/gal= 400 lb
Therefore the amount of salt is in the tank when it is about to overflow = 400 lb of salt
Answer:
0.25
Step-by-step explanation:
3/12 = 1/4
1÷4= 0.25
To prove:

Solution:

Multiply first term by
and second term by
.

Using the identity: 

Denominators are same, you can subtract the fractions.

Using the identity: 

Using the identity: 

------------ (1)

Using the identity: 


------------ (2)
Equation (1) = Equation (2)
LHS = RHS

Hence proved.
We have that 1 in----- 2.54 cm
10 in--------X
x=10*2.54=25.4 cms
the answer is 2.54 cms