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Sever21 [200]
4 years ago
5

What value(s) of x will make each equation below true? 2x – 6 = 3x +1-x-7

Mathematics
1 answer:
puteri [66]4 years ago
8 0

The answer is any value that you put in for x would make the equation true. When you simplify the whole equation it looks like this: 2x - 6 = 2x - 6, therefor you could replace x with any value.

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Which answer is equivalent to 4 1/3*4 1/6?<br> a. 16<br> b .6√​16<br> c. 2<br> d. 3√​4
Talja [164]

Answer:

<h2>c. 2</h2>

Step-by-step explanation:

4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2

5 0
3 years ago
1) g=-y+c/x, solve for X
Sindrei [870]

Answer:

the solution  x = \frac{c}{g-y}

Step-by-step explanation:

<u>Step 1:-</u>

Given problem g=\frac{-y+c}{x}

here l.cm is x

g = \frac{x y+c}{x}

cross multiplication we get ,

g x = x y +c

<u>Step 2</u>:-

subtracting x y on both sides , we get

g x - x y = c

taking common 'x' we get,

x(g-y) = c

<u>Final answer</u>:-

x = \frac{c}{g-y}

3 0
4 years ago
How to memorise times tables
kaheart [24]
Its very hard to memorise them but if you practice and keep practicing you might get the hang of them. But heres a little trick alright? For the 11ths tables every except 12 will be 11,22,33 etc.. for instance 5 times 11 equals 55 or 8 times 11 equals 88.
6 0
3 years ago
Please take a look and help if you can!
alukav5142 [94]

Answer:

see explanation

Step-by-step explanation:

1

The area of a rectangle = length × width

2

To find the width, divide the area by the length

3

width = \frac{area}{length} = \frac{3x^2+9x}{3x}

To simplify divide each term on the numerator by 3x

= \frac{3x^2}{3x} + \frac{9x}{3x} = x + 3 ← width

8 0
3 years ago
SAVING/INVESTING
elena-14-01-66 [18.8K]
I don’t know the answer to this but I have an app called Socratic, it helps out with problems like this, download it and take a picture of what you are looking for, and it will give you the answers. I hope this helps..
4 0
3 years ago
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