You have $15 and admission is $5, so you know have $10 before doing any games. If you wanted to play 12 games, you would need $10.20, which you do not have. But, if you wanted to play 11 games, then you would need $9.35, which is just under $10.
So the maximum amount of games that you could play would be 11 games.
For this case we have the following equation:
Let
We have:
By definition, given an equation of the form
The quadratic formula, to find the solution can be written as:
In this case we have:
Substituting in the quadratic formula we have:
See attached image
Answer:
Option B
(10(1-(1/2)^5)/1-(1/2) =
20(1-1/32)
=155/8
Answer:
the train leave was in JIt room but I am not sure how to make and the other way
Step-by-step explanation:
ok aw and a few of them have been missing out in all of the following is the comparatives on a new