The answer for this would be
C = 5000 + 200t
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
9 +3 = 12 students
9 are male
1st = 9/12 = 3/4
2nd = 8/11
3/4 * 8/11 = 6/11
Answer = D) 6/11
Paula would be 14 times 6 or 84
Tina would be 13 times 8 or 104
So tina made more
More specifically 32 goes into 82, 2.5625 times.
