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3 years ago

If a corporation has two classes of common stock, what is typically unique about the second or class b common stock?

1 answer:

5 0

If a corporation has two classes of common stock, the unique thing about the second or class b common stock would be: <span>It has inferior dividend payments.
</span>Class b commons stock tend to be cheaper compared to class A common stock. Of course, to balance it out, the Company will give more dividend to the type A compared to the type B common stock

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What does the quantity theory speculate about the cause of inflation?

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3 years ago

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4 years ago

Read 2 more answers

Look at the following email (attached). Name two good email netiquette practices used in the

Kipish [7]

Two good email etiquettes practices used in email are:

Inserting a Subject
Keep the email short and restricted to three paragraphs.

Two bad email etiquettes used in the email above are:

Indiscriminate use of the exclamation mark
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brainly.com/question/11498233
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1 year ago

A university officer wants to know the proportion of registered students that spend more than 20 minutes to get to school. He se

vlada-n [284]

Answer:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

$n\hat p =25*0.52= 13 \geq 10$

$n(1-\hat p) = 25*(1-0.52) =12 \geq 10$

So then we satisfy this condition

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So then the answer for this case would be:

a. Yes.

Explanation:

For this case we assume that the question is: If in the experiment described we can use the normal approximation for the proportion of interest.

For this case we have a sample of n =25

And we are interested in the proportion of registered students that spend more than 20 minutes to get to school.

X = 13 represent the number of students in the sample selected that have a time more than 20 min.

And then the estimated proportion of interest would be:

$\hat p = \frac{X}{n}= \frac{13}{25}= 0.52$

And we want to check if we can use the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So in order to do this approximation we need to satisfy some conditions listed below:

1) We need a random sample. For this case we assume that the sample selected was obtained using the simple random sampling method.

2) We need to satisfy the following inequalities:

$n\hat p =25*0.52= 13 \geq 10$

$n(1-\hat p) = 25*(1-0.52) =12 \geq 10$

So then we satisfy this condition:

3) 10% condition. For this case we assume that the random sample selected n represent less than 10% of the population size N . And for this case we can assume this condition.

So then since all the conditions are satisfied we can conclude that we can apply the normal approximation given by:

$p \sim N (\hat p, \sqrt{\frac{\hat p (1-\hat p)}{n}})$

So then the answer for this case would be:

a. Yes.

3 0

3 years ago