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2 years ago

1.What is the solution to the system of equations?

Mathematics

1 answer:

Ludmilka [50]2 years ago

8 0

1. x=4, y=0
3. x=2.6666, y=0.3333

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How do I solve log(2)t^3-1=-3?

Ne4ueva [31]

Assuming you mean
$log_2(t^3-1)=-3$
remember
$log_a(b)=c$ translates to $a^c=b$
translate

$log_2(t^3-1)=-3$ translates to $2^{-3}=t^3-1$
$\frac{1}{2^3} =t^3-1$
$\frac{1}{8} =t^3-1$
add 1 to both sides
$\frac{9}{8} =t^3$
cube root both sides
$\frac{ \sqrt[3]{9} }{2}=t$

3 0

3 years ago

Please help me this is a test

Pepsi [2]

Answer:

B. 2

Step-by-step explanation:

For x = 2, w(x) = 3, t(x) = - 1

w(x) + t(x) = 3 + (-1) = 3 - 1 = 2

8 0

3 years ago

Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

6 0

2 years ago

Feliz is looking at a cyclic quadrilateral EFGH. He says, "I'm not convinced that opposite

attashe74 [19]

If the angle G is moved to a different spot in the circle the angle FGH and angle FEH in the cyclic quadrilateral will change to make it supplementary.

<h3 /><h3>What is a cyclic quadrilateral?</h3>

A cyclic quadrilateral is quadrilateral inscribed in a circle. It has all its vertices on the circumference of the circle.

Opposite angles in a cyclic quadrilateral are supplementary angles. That means they add up to 180 degrees.

Therefore, if he adjust point G to a different spot on the circle, angle FGH and FEH will adjust to become supplementary.

learn more on cyclic quadrilateral here: brainly.com/question/27884509

#SPJ1

8 0

1 year ago

Write an expression to describe the sequence below. Use n to represent the position of a

MrRa [10]

Answer:

n+1=x-1

Step-by-step explanation:

as n goes up, x decreases by 1 each time

7 0

2 years ago