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Alekssandra [29.7K]
3 years ago
14

6 Times what equals 8?

Mathematics
1 answer:
lubasha [3.4K]3 years ago
3 0
To solve this, do 8 division 6, the answer should be 1.3333...

if you convert that to a fraction, it should be 1 1/3
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Veronika [31]

Answer:

the answer is B

Step-by-step explanation:


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Brittany is at a restaurant. Her bill is $48 plus 15%. She gave an $100. How much did she get back?
DanielleElmas [232]
She got 44.80 dollars back
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Read 2 more answers
The midpoint of is
Degger [83]

Answer:

The answer is 0/2

Step-by-step explanation:

The second y - the first y / the second x - the first x.

Step 1: 1 - 1 / 5 - 3

Step 2: 0 / 5 - 3

Step 3: 0 / 2

8 0
3 years ago
Victoria recently switched to a new electric company. If she uses between 0 and 400 kilowatt-hours (kWh) of electricity per mont
Gekata [30.6K]

Answer:

see the explanation

Step-by-step explanation:

<em><u>The question is </u></em>

Identify the domain and the range, using words and inequalities

Let

x -----> the number of kilowatt-hours (kWh) of electricity per month

y ----> the price per month

we know that

Part 1) For the value of x between 0 kWh and 400 kWh

0\ kWh \leq x < 400\ kWh

The price is equal to

y=\$30

therefore

The domain is the interval ------> [0,400)

The domain is all real numbers greater than or equal to 0 kWh  and less than 400 kWh

The range is ($30)

The range is equal to $30

Part 2) For the value of x equal to 400 kWh or more per month

x\geq 400\ kWh

The domain is the interval -----> [400, infinite)

The domain is all real numbers greater than or equal to 400 kWh

The price is

y=0.097x

<em>Find the range</em>

For x=400 kWh

y=0.097(400)=\$38.8

so

y\geq \$38.8

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7 0
3 years ago
2(a³+b²+11)+1(3+a³+b+11)
Ann [662]

Answer:

2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

2(a^3+b^2+11)+1(3+a^3+b+11)

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14

Therefore, 2(a^3+b^2+11)+1(3+a^3+b+11) is equal to:

2a^3+2b^2+22+a^3+b+14

Now, combining like terms using the commutative property of addition, we get:

=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36

Therefore, the simplified form is 3a^3+2b^2+b+36

8 0
3 years ago
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