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3 years ago

6 Times what equals 8?

Mathematics

1 answer:

lubasha [3.4K]3 years ago

3 0

To solve this, do 8 division 6, the answer should be 1.3333...

if you convert that to a fraction, it should be 1 1/3

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If anyone can help me solve this problem?

Veronika [31]

Answer:

the answer is B

Step-by-step explanation:

4 0

3 years ago

Brittany is at a restaurant. Her bill is $48 plus 15%. She gave an $100. How much did she get back?

DanielleElmas [232]

She got 44.80 dollars back

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3 years ago

Read 2 more answers

The midpoint of is

Degger [83]

Answer:

The answer is 0/2

Step-by-step explanation:

The second y - the first y / the second x - the first x.

Step 1: 1 - 1 / 5 - 3

Step 2: 0 / 5 - 3

Step 3: 0 / 2

8 0

3 years ago

Victoria recently switched to a new electric company. If she uses between 0 and 400 kilowatt-hours (kWh) of electricity per mont

Gekata [30.6K]

Answer:

see the explanation

Step-by-step explanation:

The question is

Identify the domain and the range, using words and inequalities

Let

x -----> the number of kilowatt-hours (kWh) of electricity per month

y ----> the price per month

we know that

Part 1) For the value of x between 0 kWh and 400 kWh

$0\ kWh \leq x < 400\ kWh$

The price is equal to

$y=\$30$

therefore

The domain is the interval ------> [0,400)

The domain is all real numbers greater than or equal to 0 kWh and less than 400 kWh

The range is ($30)

The range is equal to $30

Part 2) For the value of x equal to 400 kWh or more per month

$x\geq 400\ kWh$

The domain is the interval -----> [400, infinite)

The domain is all real numbers greater than or equal to 400 kWh

The price is

$y=0.097x$

Find the range

For x=400 kWh

$y=0.097(400)=\$38.8$

$y\geq \$38.8$

The range is the interval -----> [38.8, infinite)

7 0

3 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

3 years ago