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2 years ago

Three friends all have ages that are consecutive integers. The sum of their ages is 48. what is the age of the eldest friend?

Mathematics

2 answers:

Xelga [282]2 years ago

8 0

The answer to this is C.17

Schach [20]2 years ago

4 0

Answer:

C.17 years old

Step-by-step explanation:

consecutive means that they come after each other

17+16+15=48

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Dolbear's law states the relationship between the rate at which Snowy Tree Crickets chirp and the air temperature of their envi

tia_tia [17]

I assume that if we write the equation in its mathematical form it will appear like this:
T = 50 + (N - 40)/4
Substituting the value of T given,
58 = 50 + (N-40)/4
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2 years ago

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A radioactive substance decays exponentially. A scientist begins with 190 milligrams of a radioactive

worty [1.4K]

Answer: 65.1 (mg)

Step-by-step explanation:

$y=190*e^{-a*t}\\\\Calculate\ a:\\\\t=33,y=95(mg)\\\\190*e^{-a*33}=95\\\\e^{-a*33}=0.5\\\\-a*33=ln(0.5)\\\\a=\dfrac{ln(\dfrac{1}{2}) }{-33} \\\\a=0,02100... \approx{0.021}\\\\If\ t=51\ h, y=190*e^{-0.02100*51}=65.09167...\approx{65.1}$

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2 years ago

Casey buys a bracelet. She pays for the bracelet and pays \$0.72$0.72 in sales tax. The sales tax rate is 6\%6%. What is the ori

aleksklad [387]

Answer:

$12.00

Step-by-step explanation:

If they paid $0.72 in tax and tax is 6% or .06 then you could create an equation like this: x * .06 = .72 with x representing the original cost of the bracelet. Now you can just solve for x like so:

x * .06 = .72

÷.06 ÷.06

x = 12

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2 years ago

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There are 138 people seated at a table in a banquet hall. Each table can seat 12 people. All the tables are full except one. How

gulaghasi [49]

There are 11 full tables, because when you divide 138 by 12 you get 11 remainder 6. So there is 11, because 12 people are at 11 tables and 6 at one!

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2 years ago

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How do I solve this ?

timofeeve [1]

Answer:

$\large\boxed{\{4,\ 7,\ 10\}}$

Step-by-step explanation:

$X\ \cup\ Y\\\text{The union of a collection of sets is the set of all elements in the collection.}\\\\X\ \cap\ Y\\\text{The intersection}\ X\cap Y\ \text{of two sets X and Y is the set that contains}\\\text{all elements of X that also belong to Y, but no other elements.}\\\\A'\\\text{When A is a subset of a given set U, the absolute complement A}\\\text{is the set of elements in U, but not in A.}$

$U=\{3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9,\ 10\}\\A=\{4,\ 6,\ 8\}\\B=\{3,\ 4,\ 7,\ 10\}\\C=\{3,\ 5,\ 9\}\\\\A\ \cup\ B=\{4,\ 6,\ 8\}\ \cup\ \{3,\ 4,\ 7,\ 10\}=\{3,\ 4,\ 6,\ 7,\ 8,\ 10\}\\C'=\{3,\ 4,\ 5,\ 6,\ 7,\ 8,\ 9,\ 10\}-\{3,\ 5,\ 9\}=\{4,\ 6,\ 7,\ 8,\ 10\}\\B\ \cap\ C'=\{3,\ \b4,\ \b7,\ \b1\b0\}\ \cap\ \{\b4,\ 6,\ \b7,\ 8,\ \b1\b0\}=\{\b4,\ \b7,\ \b1\b0\}\\\\(A\ \cup\ B)\ \cap\ (B\ \cap\ C')=\{3,\ \b4,\ 6,\ \b7,\ 8,\ \b1\b0\}\ \cap\ \{\b4,\ \b7,\ \b1\b0\}=\{\b4,\ \b7,\ \b1\b0\}$

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3 years ago