The first thing we are going to do is find the area of the field. To do this we are going to use the area of a square formula:

Were

is the area in square kilometers

is one of the sides of the square
We know for our problem that the side lengths of the field are 0.9 kilometers, so

. Lets replace that value in our formula to find

:

Now, to find the population density of the filed, we are going to use the population density formula:

where

is the population density in <span>in burrows per square kilometer
</span>

is the number of burrows

is the are of the field
We know that

and

, so lets replace those values in our formula:


We can conclude that the <span>density of prairie dog burrows is approximately
2444 burrws per square kilometer.</span>
I and 4i
let's say if you have i you can automatically think there is a one in front of it so one term like this (i) could look like this 1i and any number with the same variable or letter are like terms
hope this helps
The answer i came up with is 0.68 i don't know if thats what you need or not. hopefully i helped.
Answer:
-2.7 < y
Step-by-step explanation:
2.9 < 5.6+y
Subtract 5.6 from each side
2.9-5.6 < 5.6-5.6+y
-2.7 < y
Answer:
It's A :)
Step-by-step explanation:
30/2 is 15
15 is a whole number so it applies to everything except for irrational numbers
Hope this helps :)