What is the equation of a circle with a center at (–4, 0) that passes through the point (–2, 1)? x2 + (y + 4)² = StartRoot 5 End
Root (x – 1)² + (y + 2)² = 5 (x + 4)² + y² = 5 (x + 2)² + (y – 1)² = StartRoot 5 EndRoot
2 answers:
Answer:
C. (x + 4)² + y² = 5
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
no
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Answer:
(x+2)^2 + (y-4)^2 = 65
Step-by-step explanation:
r^2 = (4-(-4))^2 + (-1-(-2))^2 = 65
center = (-2, 4) so you add 2 to x and subtract 4 from y
Now plug the x value into 9x + 2
Hope that helps!
