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3 years ago

Please I just need help with these two problems

Mathematics

2 answers:

Svetllana [295]3 years ago

8 0

34. 3d - 4 + d = 8d - (-12)

3d + d - 4 = 8d + 12

4d - 4 = 8d + 12

4d - 8d - 4 + 4 = 8d - 8d + 12 + 4

-4d = 16

(-4d)/(-4) = 16/(-4)

d = -4

Answer: d = -4

35. f - 6 = -2f + 3(f - 2)

f - 6 = -2f + 3 * f - 3 * 2

f - 6 = -2f + 3f - 6

f - 6 = f - 6

f - f - 6 + 6 = f - f - 6 + 6

0 = 0

Since 0 = 0 is a true statement, that means that there is an infinite number of solutions.

Answer: The solution is all real numbers.

Oksana_A [137]3 years ago

7 0

$3d-4+d=8d+12 \implies \\4d-4=8d+12 \implies-4d=16 \implies\\ d=-4$

$f-6=-2f+3(f-2) \implies \\ f-6=-2f+3f-6 \implies\\ f-6=f-6 \implies\\ 0=0 \implies \text{ all real numbers are a solution to this problem}$

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Factorise 21x-14y Pls try answer its for my homework thx

prohojiy [21]

$21x-14y \\ \\ GCF = 7 \\ \\ 7( \frac{21x}{7} + \frac{-14y}{7} ) \ / \ factor \ out \ gcf \\ \\ 7(3x - 2y) \ / \ simplify \\ \\ Answer: \fbox {7 (3x - 2y)}$

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3 years ago

Complete the equation of the line through (-10,-7)(−10,−7)(, minus, 10, comma, minus, 7, )and (-5,-9)(−5,−9)(, minus, 5, comma,

Tanzania [10]

Answer:

$y = -\frac{2}{5}\cdot x - 11$

Step-by-step explanation:

First, the slope is determined by using the following expression:

$m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m = \frac{-7-(-9)}{-10 - (-5)}$

$m = -\frac{2}{5}$

The y-intercept is found by using the line equation, the slope and one point:

$y = m \cdot x +b$

$b = y - m\cdot x$

$b = -7 - \left(-\frac{2}{5}\right)\cdot (-10)$

$b = -11$

The equation of the line is:

$y = -\frac{2}{5}\cdot x - 11$

7 0

3 years ago

Use the rules of exponents to evaluate and simplify the following expression. Type all without negative exponents. Do not distri

Rainbow [258]

We are given (xy)^(-3).

This leads to 1/(xy)^3.

You see, going from the top to the bottom alters the sign of the exponent to its opposite.

ANSWER: 1/(x^3•y^3)

Did you follow?

5 0

3 years ago

Given a polynomial f(x), if (x − 4) is a factor, what else must be true?

ollegr [7]

Answer:

$f(4)=0$

Step-by-step explanation:

The Remainder Theorem states that when you divide a polynomial $f(x)$ by a linear factor $(x-a)$ , where $a$ is a constant, the remainder is $f(x)$ evaluated at $x=a$

Moreover, according to the Factor Theorem, an extension of the Remainder Theorem, if the remainder of the function $f(x)$ is 0 when evaluated at $x=a$ , then $(x-a)$ is said to be a factor of the polynomial $f(x)$

Given the 2 theorems above, it follows that if $(x-4)$ is a factor of $f(x)$ , then the remainder is equal to 0 when $f(x)$ is evaluated at $x=4$