Answer:
Area of the doormat is <u>0.45 square yards</u>.
Step-by-step explanation:
Given:
The dimensions of a rectangular doormat are 0.6 yard and 75% of a yard.
Now, to find the area in square yards of the door mat.
75% of a yard.
75% of 1 yard.
![\frac{75}{100} \times 1](https://tex.z-dn.net/?f=%5Cfrac%7B75%7D%7B100%7D%20%5Ctimes%201)
![=0.75\times 1](https://tex.z-dn.net/?f=%3D0.75%5Ctimes%201)
![=0.75\ yard.](https://tex.z-dn.net/?f=%3D0.75%5C%20yard.)
The dimensions are 0.6 yard and 0.75 yard.
Now, to get the area of doormat:
![Area=0.6\times 0.75](https://tex.z-dn.net/?f=Area%3D0.6%5Ctimes%200.75)
![Area=0.45\ square\ yard.](https://tex.z-dn.net/?f=Area%3D0.45%5C%20square%5C%20yard.)
Therefore, area of the doormat is 0.45 square yards.
Answer:
<em>8 adults</em>
Step-by-step explanation:
1.) $78 - $6 = $72
2.) $72/$9 = 8
Step-by-step explanation:
circumference of a circle
2×pi×r
area of a circle
pi×r²
r = 8 yd
circumference is
2×3.14×8 = 3.14×16 = 50.24 yd
area is
3.14×8² = 3.14×64 = 200.96 yd²
Step 1: Find the area of the larger rectangle
Area of a rectangle = base x height
Area = 4 x 3 = 12
Step 2: Find the area of the other rectangle
The tricky part about this one is that we aren't given the length of this rectangle. We do know, however, that the whole base of the figure is 6 and 3 units are taken up by the first rectangle. Therefore, the length of this rectangle is 3.
Area = 2 x 3 = 6
Step 3: Find the area of the figure
Now that we know the area of both rectangles by themselves, all that's left to do is add them up.
6 + 12 = 18
Answer: 18
Hope this helps!
Answer:
![1. (5 \times 10^3) \times (9 \times 10^7) = 45 \times 10^{10}\\2. (7 \times 10^5) \div (2 \times 10^2) = 3.5 \times 10^3](https://tex.z-dn.net/?f=1.%20%285%20%5Ctimes%2010%5E3%29%20%5Ctimes%20%289%20%5Ctimes%2010%5E7%29%20%20%3D%2045%20%5Ctimes%2010%5E%7B10%7D%5C%5C2.%20%287%20%5Ctimes%2010%5E5%29%20%5Cdiv%20%282%20%5Ctimes%2010%5E2%29%20%20%3D%203.5%20%5Ctimes%2010%5E3)
Step-by-step explanation:
Here, the given expressions are:
![1. (5 \times 10^3) \times (9 \times 10^7)\\2. (7 \times 10^5) \div (2 \times 10^2)](https://tex.z-dn.net/?f=1.%20%285%20%5Ctimes%2010%5E3%29%20%5Ctimes%20%289%20%5Ctimes%2010%5E7%29%5C%5C2.%20%287%20%5Ctimes%2010%5E5%29%20%5Cdiv%20%282%20%5Ctimes%2010%5E2%29)
Now, the LAWS OF EXPONENTS state that:
![1. a^ m \times a^n = a^{(m+n)}\\ 2. a^m \div a^n = a ^{(m-n)}](https://tex.z-dn.net/?f=1.%20a%5E%20m%20%5Ctimes%20a%5En%20%3D%20a%5E%7B%28m%2Bn%29%7D%5C%5C%202.%20a%5Em%20%5Cdiv%20a%5En%20%3D%20a%20%5E%7B%28m-n%29%7D)
Using above laws, we get:
![1. (5 \times 10^3) \times (9 \times 10^7)\\= (5 \times 9 ) \times ( 10^7\times 10^3)\\= 45 \times (10^{(7+3)}) = 45 \times 10^{10}\\\implies (5 \times 10^3) \times (9 \times 10^7) = 45 \times 10^{10}](https://tex.z-dn.net/?f=1.%20%285%20%5Ctimes%2010%5E3%29%20%5Ctimes%20%289%20%5Ctimes%2010%5E7%29%5C%5C%3D%20%285%20%20%5Ctimes%209%20%29%20%5Ctimes%20%28%2010%5E7%5Ctimes%2010%5E3%29%5C%5C%3D%2045%20%5Ctimes%20%2810%5E%7B%287%2B3%29%7D%29%20%20%3D%2045%20%5Ctimes%2010%5E%7B10%7D%5C%5C%5Cimplies%20%285%20%5Ctimes%2010%5E3%29%20%5Ctimes%20%289%20%5Ctimes%2010%5E7%29%20%20%3D%2045%20%5Ctimes%2010%5E%7B10%7D)
![2. (7 \times 10^5) \div (2 \times 10^2)\\= \frac{(7 \times 10^5)}{(2 \times 10^2)} = \frac{7}{2} \times\frac{10^5}{10^2} \\ =3.5 \times 10^{(5-2)} = 3.5 \times 10^3\\\implies(7 \times 10^5) \div (2 \times 10^2) = 3.5 \times 10^3](https://tex.z-dn.net/?f=2.%20%287%20%5Ctimes%2010%5E5%29%20%5Cdiv%20%282%20%5Ctimes%2010%5E2%29%5C%5C%3D%20%5Cfrac%7B%287%20%5Ctimes%2010%5E5%29%7D%7B%282%20%5Ctimes%2010%5E2%29%7D%20%20%3D%20%5Cfrac%7B7%7D%7B2%7D%20%20%5Ctimes%5Cfrac%7B10%5E5%7D%7B10%5E2%7D%20%20%20%5C%5C%20%3D3.5%20%5Ctimes%2010%5E%7B%285-2%29%7D%20%20%3D%203.5%20%5Ctimes%2010%5E3%5C%5C%5Cimplies%287%20%5Ctimes%2010%5E5%29%20%5Cdiv%20%282%20%5Ctimes%2010%5E2%29%20%20%3D%203.5%20%5Ctimes%2010%5E3)