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3 years ago

Yolanda runs 5 miles in 38 minutes how much would she run in 57 minutes

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

7 0

Answer:

Step-by-step explanation:

Assuming she runs at the same pace, this will be a simple problem to solve. First we have to find that rate. She ran 5 miles in 38 minutes. This means she ran about 0.131 miles per minute. Then we just have to multiple that rate by 57 minutes to find out that at the same pace she would have run about 7.5 miles.

Hope I Helped :)

kkurt [141]3 years ago

4 0

Answer:

7.5 miles

Step-by-step explanation:

38/5=7.6

57/7.6=7.5

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Salsk061 [2.6K]

Answer: -6

Step-by-step explanation: -|b-a|

-|-2-4|

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3 years ago

Read 2 more answers

A street has parallel curbs 40 feet apart. A crosswalk bounded by two parallel stripes crosses the street at an angle. The lengt

andreev551 [17]

Answer:

The distance, in feet, between the strip = 12 feet.

Step-by-step explanation:

From the figure attached in relation with the question, we can deduce that crosswalk is a parallelogram where

CD/AB = CE/AE

CD = 40

CE = 50

AE = 15

Let AB = x

50x = 15 × 40

X = 12

The distance, in feet, between the strip is therefore 12 feet

6 0

3 years ago

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

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3 years ago

I need help finding the value of y

Dahasolnce [82]

Answer:

Value of y be 5

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3 years ago

A tennis ball travels at a speed of 120 miles per hour. what is the rate in feet per second?

LUCKY_DIMON [66]

Answer:176

Step-by-step explanation:

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3 years ago

Yolanda runs 5 miles in 38 minutes how much would she run in 57 minutes​

Yolanda runs 5 miles in 38 minutes how much would she run in 57 minutes