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3 years ago

Which are correct representations of the inequality 6x > 3 + 4/2x-112 Select three options

Mathematics

1 answer:

cricket20 [7]3 years ago

4 0

Answer:

The Third one

Step-by-step explanation:

-2x>-1

x<1\2 Because when you divide by negative the symbol is changed.

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Help mememememme please ☹️

Dmitriy789 [7]

An exterior angle is formed by one side of the triangle, and a side EXTENDED outside the triangle. Two angles are like that, ∠4 and ∠2.

Angle 3 is NOT an exterior angle because it is made up of two extended sides. It does not use one of the sides of the triangle.

3 0

3 years ago

Five more than three times a number is 197. find the mlnumber

insens350 [35]

Answer:

Step-by-step explanation:

If the number is x we have the equation:-

3x + 5 = 197

Subtract 5 from both sides:-

3x = 192

x = 192/3

x = 64

7 0

3 years ago

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

MVUT =175, mVUJ=17x-3, and mJUT=17x+8. Find x

kotykmax [81]

The diagram of the three angles is shown below with point U as the point where all three lines meet.

Angles property: Angles around a point add up to 360°

We set up an equation

$175+17x-3+17x+8=360$
$180+34x=360$
$34x=360-180$
$34x=180$
$x= \frac{180}{34}= \frac{90}{17}$

5 0

3 years ago

Find the equation of the line passing through the points (5,3) and (5,−6).

allsm [11]

Answer:

In y-intercept form: X = 5

Step-by-step explanation:

$(\frac{-6-3}{5-5} ) = \frac{-9}{0}$

Becuz the slope is Undefined

7 0

3 years ago