V1=(-2,4)=(x1,y1)→x1=-2, y1=4
V2=(4,0)=(x2,y2)→x2=4, y2=0
V3=(2,-3)=(x3,y3)→x3=2, y3=-3
V4=(x4,y4)→x4=?, y4=?
V1-V2
dx=x2-x1=4-(-2)=4+2→dx=6
dy=y2-y1=0-4→dy=-4
V4-V3
dx=x3-x4→6=2-x4
Solving for x4:
6=2-x4→6-2=2-x4-2→4=-x4→(-1)(4=-x4)→-4=x4→x4=-4
dy=y3-y4→-4=-3-y4
Solving for y4:
-4=-3-y4→-4+3=-3-y4+3→-1=-y4→(-1)(-1=-y4)→1=y4→y4=1
V4=(x4, y4)→V4=(-4, 1)
Answer: The coordinates of the fourth vertex are (-4,1)
Answer:
−1(5−2)(5+2)
Step-by-step explanation:
Eliminate redundant parentheses
(−11²+6)−1(14² +2)
Distribute
−11² + 6 -- 1(14² +2)
−11² + 6 - 14² − 2
You would divide the two numbers to get 54
Answer : 44y. Put why because it’s repeated
We are given that:
side length = 8 3/2 inches = 9.5 inches
the rule for the area is: A = s^2
Substitute with the side length in the rule given to get the area as follows:
Area = s^2 = (9.5)^2 = 90.25 inch^2