All categories

3 years ago

How to turn a percent into a decimal

Mathematics

2 answers:

vitfil [10]3 years ago

4 0

To turn a percent into a decimal, move the decimal point over to the left two places.

For example, 25% would be .25 as a decimal.

An easy way to remember how many places the decimal point moves is by looking at the percent sign. It has two circles on either side of the slash, so two circles = two places.

Elena-2011 [213]3 years ago

3 0

Step 1: Find the percentage in the problem.

Step 2: Create a fraction by putting the fraction as the numerator over 100.

Step 3: Divide the numerator "the percent" by the denominator which is 100.

Example:

32% = ?

$\frac{32}{100}$

32 ÷ 100 = .32

You might be interested in

Help marking brainly first awnser

solong [7]

Option as is correct hope this helped have a nice day

8 0

3 years ago

Explain how to solve this problem in your own words.

natta225 [31]

Answer:

3 m^8

Step-by-step explanation:

We know that a^b / a^c = a^( b-c) so using the quotient rule for exponents

3 * m^( 7 - -1)

3 *m^(8)

7 0

3 years ago

33. Suppose you were on a planet where the

tatyana61 [14]

Answer:

a) 3.675 m

b) 3.67m

Explanation:

We are given acceleration due to gravity on earth = $9.8ms^-2$

And on planet given = $2.0ms^-2$

A) Since the maximum jump height is given by the formula

$\mathrm{H}=\frac{\left(\mathrm{v} 0^{2} \times \sin 2 \emptyset\right)}{2 \mathrm{g}}$

Where H = max jump height,

v0 = velocity of jump,

Ø = angle of jump and

g = acceleration due to gravity

Considering velocity and angle in both cases

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 2}{\mathrm{g} 1}$

Where H1 = jump height on given planet,

H2 = jump height on earth = 0.75m (given)

g1 = 2.0 $ms^-2$ and

g2 = 9.8 $ms^-2$

Substituting these values we get H1 = 3.675m which is the required answer

B) Formula to find height of ball thrown is given by

$\mathrm{h}=(\mathrm{v} 0 * \mathrm{t})+\frac{\mathrm{a} *\left(t^{2}\right)}{2}$

which is due to projectile motion of ball

Now h = max height,

v0 = initial velocity = 0,

t = time of motion,

a = acceleration = g = acceleration due to gravity

Considering t = same on both places we can write

$\frac{\mathrm{H} 1}{\mathrm{H} 2}=\frac{\mathrm{g} 1}{\mathrm{g} 2}$

where h1 and h2 are max heights ball reaches on planet and earth respectively and g1 and g2 are respective accelerations

substituting h2 = 18m, g1 = 2.0 $ms^-2$ and g2 = 9.8 $ms^-2$

We get h1 = 3.67m which is the required height

6 0

3 years ago

Why do I miss her? :/

Dima020 [189]

Answer:

because you probably liked her or you just miss her company ya know talking with her or just messing around lol

4 0

3 years ago

Classify each event as simple or compound

Dmitry [639]

Answer:

1. Compound

2. Simple

3. Simple

4. Compound

Step-by-step explanation:

The way I differentiated these was based on the quantitivity of each scenario. I related it to compound and simple sentences. For example, when one act was committed, it was clearly singular & simple. But if there was two actions consecutively, I'd consider that compound.

4 0

3 years ago

Read 2 more answers