Answer:
tan2θ = 4√2/7
Step-by-step explanation:
Given sin theta=1/3 and 0 < theta< π/+
Required
tan 2 theta
tan2 theta = 2tanθ/1-tan²θ
Get tan θ
sinθ = opp/hyp
adj = √3²-1²²
adj = √9-1
adj = √8
tanθ = opp/adj = 1/2√2
tan2 theta = 2(1/2√2/1-(1/2√2)²
tan2θ = 1/√2/1-1/8
tan2θ = 1/√2/7/8
tan2θ = 8/7√2
Rationalize
tan2θ = 8√2/14
tan2θ = 4√2/7
Answer:
853,125
Step-by-step explanation:
Umhhh u can use a calculator… or write it down and slowly break down solve it like that.
Hope this helps, good luck! ;)
I want to say that shows a decreasing interval, since it is going downwards.
In order to answer the question, we simply substitute the value of p and q to the given expression and solve. We do as follows:
<span>P^2q^2+pq–q^3–p^3
</span>0.5^2(-0.5)^2+0.5(-0.5)–(-0.5)^3–(0.5)^3
-3/16 or -0.1875
Hope this answers the question. Have a nice day.
