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4 years ago

Kristin bought three $48.50 shirts at a V2-price sale. Dawn bought three of the

Mathematics

1 answer:

juin [17]4 years ago

4 0

Dawn made the better buy because they both sent the same amount of money but Dawn got one more for free.

Hope I helped

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If $1000 is divided equally amung 12 people about how much will each person reserve?

Dmitry_Shevchenko [17]

$1,000/12 = 83.3 repeated
Each person will reserve about $83.

3 0

3 years ago

Read 2 more answers

Find the sum of each series, if it exists<br>91 + 85 + 79 + … + (29)

Natali [406]

Answer:

651.

Step-by-step explanation:

Note: In the given series it should be -29 instead of 29 because 29 cannot be a term of AP whose first term is 91 and common difference is -6.

Consider the given series is

$91+85+79+...+(-29)$

It is the sum of an AP. Here,

First term = 91

Common difference = 85 - 91 = -6

Last term = -29

nth term of an AP is

$a_n=a+(n-1)d$

where, a is first term and d is common difference.

$-29=91+(n-1)(-6)$

$-29-91=(n-1)(-6)$

$\dfrac{-120}{-6}=(n-1)$

$20=(n-1)$

$n=20+1=21$

Sum of AP is

$Sum=\dfrac{n}{2}[\text{First term + Last term}]$

$Sum=\dfrac{21}{2}[91+(-29)]$

$Sum=\dfrac{21}{2}[62]$

$Sum=651$

Therefore, the sum of given series is 651.

5 0

3 years ago

Anthony observes that when people are leaving class, about 50% turn left and about 50% turn right. Anthony wants to estimate the

Viktor [21]

The probability is 7/10.

There are 14 outcomes in this simulation with fewer than 3 left turns, out of 20 times the simulation was run:
14/20 = 7/10

6 0

3 years ago

What is the simplified form of 3 Start Root 5 c End Root times Start Root 15 c cubed End root? (worth 30 brainily points)

aleksley [76]

Answer:

A. 15 c squared Start Root 3 End Root

Step-by-step explanation:

$3\sqrt{5c} *\sqrt{15c^3} \\$

Multiply the terms inside the square roots together

$3\sqrt{75c^4}$

Look for items that are perfects squares

$3\sqrt{25*3*c^4}$

We can separate terms inside the square root into separate square roots

$3\sqrt{25} *\sqrt{3}*\sqrt{c^4}$

$3*5 *\sqrt{3} *c^2$

Combine like terms

$15c^2\sqrt{3}$

8 0

4 years ago

What is the true solution to 2 in e^in 5x = 2 in 15

Mkey [24]

We have to solve this equation:
$2 * ln e ^{ln(5x)}= 2 * ln 15/:2 \\ ln e ^{ln(5x)}=ln 15 \\ e ^{ln(5x)}=15 \\$
5 x = 15
x = 15 : 5
Answer:
x = 3

7 0

3 years ago

Read 2 more answers