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3 years ago

Which point could be removed in order to make the relation a function? {(–4, 3), (–5, 6), (1, 0), (–4, 5), (9, 5), (0, –7)}

1 answer:

3 0

When there are two equivalent x values, the table cannot produce a function, so you would have to remove (-4,3) or (-4,5) because they have the same x values.

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If five notebooks cost $5.25 how much would 3 cost?

34kurt

3.15. Just find the unit rate which is 1.5 and multiply that by 3

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3 years ago

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Order the following list of numbers from least to greatest <br>V35, 5.7, 17/3, 5.83<br>

irina1246 [14]

Answer:

17/3, 5.7, 5.83, √35.

Step-by-step explanation:

√35, 5.7, 17/3, 5.83

√35 = 5.916

5.7 = 5.700

17/3 = 5.667

5.83 = 5.830.

So the answer is 17/3, 5.7, 5.83, √35.

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3 years ago

A football player is running the length of a 100 yard long football field. For the first part of the field, he runs at a rate of

notka56 [123]

Answer:

$\frac{2}{5}$ th part of the field is covered in the second sprint.

Step-by-step explanation:

A football player is running the length of a 100 yard long football field.

Let player sprints x yards with the speed = 2 yards per second.

So time taken to cover x yards player will take time = $\frac{x}{2}$ seconds

Now rest distance (100 - x) yards when covered with the speed of 4 yards per second, so time taken to cover this distance = $\frac{Distance}{Speed}$

= $\frac{100-x}{4}$ seconds

Now total time taken by the player can be represented by the equation

$\frac{x}{2}+\frac{100-x}{4}=40$

Now we can solve this equation for the value of x.

$\frac{2x+100-x}{4}=40$

x + 100 = 40×4

x + 100 = 160

x = 160 - 100 = 60 yards

And length of the second part will be = 100 - 60 = 40 yards

Now the fraction of the field covered by the player in second sprint will be

= $\frac{40}{100}$

= $\frac{2}{5}$ or 40%

Therefore, $\frac{2}{5}$ th part of the field was covered in second sprint.

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3 years ago

Multiplying binomials<br> Determine the product<br> (x-3) (x-8)

MrMuchimi

X^2-24 is the answer

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3 years ago

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Can someone PLEASE help me. I really don't know...

lyudmila [28]

Hope this helps...feel free to ask for any help

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3 years ago