Answer:
yea by using a resipe
Step-by-step explanation:
Answer:
First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile
Answer:

Step-by-step explanation:
since q(x)=-4
substitute
hence
-4=12x-3
take -3 to the other side where it becomes positive
therefore
-1=12x
divide by 12
you will get the above answer