Answer:
.
Step-by-step explanation:
We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.
We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.
So there are 4 prime number in set A and total numbers are 5.
We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.
So there are 3 prime number in set B and total numbers are 4.
Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.
Therefore, the probability that both numbers are prime would be .
Answer:
Step-by-step explanation:
First method: for (x+3)^2 if you multiply (x+3)(x+3) you get x^2+6x+9 which doesn't equal x^2+9
Second way: plug in a variable for example (2+3)^2= 25 and 2^2+9=13 so 13 doesn't equal 25
The answer is f(x) = 2.9|x| and f(x) = 1.2|x + 8<span>|</span>
Answer:
1 + tan 2θ = sec 2θ
Step-by-step explanation:
cos 2θ + sin 2θ = 1
Dividing by cos 2θ we get
( cos 2θ + sin 2θ ) / cos 2θ = 1 / cos 2θ
1 + sin 2θ / cos 2θ = sec 2θ
And sin 2θ / cos 2θ = tan 2θ
Then
1 + tan 2θ = sec 2θ
Answer:
True
Step-by-step explanation: