Common difference = -16-(-20) = 4
nth term = -20+(n-1)4
Remember, you take 1/2 of b and square it to get c
c=100
(b/2)^2=c
(b/2)^2=100
sqrt oth sides
b/2=+/-10
times both sides by 2
b=+/-20
it is 20 or -20
answe ris B
yo is right
Answer:
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Step-by-step explanation:
Given:
To Find:
Equation of line passing through ( 16, -7) and is perpendicular to the line
Solution:
...........Given

Comparing with,
Where m =slope
We get
We know that for Perpendicular lines have product slopes = -1.

Substituting m1 we get m2 as

Therefore the slope of the required line passing through (16 , -7) will have the slope,
Now the equation of line in slope point form given by
Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,
Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line
is
Answer:
y = (x + 4)(x - 9)
Step-by-step explanation:
x = {-4, 9}
y = (x + 4)(x - 9)
Prisms is the answer for the question