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3 years ago

Find the distance between the points (-3, 5) and (6,5)

Mathematics

2 answers:

Igoryamba3 years ago

7 0

Answer:

Step-by-step explanation:

Since the y coordinates are the same the distance is found by looking at the x coordinates

6 - -3

6+3

The distance is 9 units

dmitriy555 [2]3 years ago

7 0

You can start by using the distance formula.

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Sin(x)=cos(90-x); therefore x=68º

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3 years ago

Part A Prove that when x > 1, a triangle with side lengths a = x2 − 1, b = 2x, and c = x2 + 1 is a right triangle. Use the Py

Nataly [62]

Step-by-step explanation:

Given : A triangle with side lengths $a = x^2-1, b = 2x, \text{ and } c = x^2 + 1$

To find : Prove that when x > 1, it is a right triangle. Use the Pythagorean theorem and the given side lengths to create an equation. Use the equation to show that this triangle follows the rule describing right triangles. Explain your steps ?

Solution :

For right triangle the Pythagorean theorem is to be satisfied.

i.e. $c^2=a^2+b^2$

Here, $a = x^2-1, b = 2x, \text{ and } c = x^2 + 1$

Substitute the values,

$(x^2+1)^2=(x^2-1)^2+(2x)^2$

$x^4+1+2x^2=x^4+1-2x^2+4x^2$

$x^4+1+2x^2=x^4+1+2x^2$

LHS=RHS

It is a right triangle.

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3 years ago

Suppose a box of Cracker Jacks contains one of 5 toy prizes: a small rubber ball, a whistle, a Captain America decoder ring, a r

lakkis [162]

Answer:

11.42 boxes

Step-by-step explanation:

For the first box bought, there is a 100% chance of getting a unique toy (since you still don't have any). E₁ = 1.

After that, there is a 4 in 5 chance of getting a unique toy from the next box, the expected number of boxes required is:

$E_2 = (\frac{4}{5})^{-1} = 1.25$

For the next unique toy, there is now a 3 in 5 chance of getting it:

$E_3 = (\frac{3}{5})^{-1} = 1.67$

Following that logic, there is a 2 in 5 chance of getting the 4th unique toy:

$E_4 = (\frac{2}{5})^{-1} = 2.5$

Finally, there is a 1 in 5 chance to get the last unique toy:

$E_5 = (\frac{1}{5})^{-1} = 5$

The expected number of boxes to obtain a full set is:

$E=E_1+E_2+E_3+E_4+E_5\\E=1+1.25+1.67+2.5+5\\E=11.42\ boxes$

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